Answer:
The maximum distance Charles will push down the trampoline ≈ 0.342 m
Explanation:
The given parameters are;
The mass of the trampoline artist, m = 75 kg
The speed with which the trampoline artist lands, v = 9.0 m/s
The value of the spring constant of the trampoline, k = 52,000 N/m
Let x represents the maximum distance Charles will push down the trampoline
Therefore, we have;
Kinetic energy = 1/2·m·v²
The kinetic energy with which the trampoline artist lands = 1/2 × 75 × 9.0² = 3037.5
The kinetic energy with which the trampoline artist lands = 3037.5 J
The potential energy stored in a spring = 1/2·k·x² = The kinetic energy with which the trampoline artist lands
∴ 1/2 × 52,000 × x² = 3037.5
∴ x = √(3037.5/(1/2 × 52,000)) ≈ 0.342
The maximum distance Charles will push down the trampoline = x ≈ 0.342 m
Answer:43.34 m
Explanation:
Given
acceleration(a)
Initial Velocity(u)=0 m/s
After 6 s fuel runs out
Velocity after 6 s
v=u+at
After this object will start moving under gravity
height reached in first 6 s
s=36 m
After fuel run out distance traveled in upward direction is
here v=0
u=12 m/s
Answer:
The ozone layer is present in the stratosphere.
The energy if of a photon is (Planck's Konstant) x (frequency).
Planck's Konstant is 6.62607004 × 10⁻³⁴ m²-kg/s .
So the photon's energy is
(6.626 × 10⁻³⁴ m²-kg/s) x (4.89 x 10¹⁴ / sec)
= (32.4 x 10⁻²⁰) m²-kg/s²
= 3.24 x 10⁻¹⁹ joule
The correct answer for the question that is being presented above is this one: "C. The negative terminal of the source of voltage is connected to the N-type material within a reverse-biased setup." the statement that accurately describes junction diodes is that t<span>he negative terminal of the source of voltage is connected to the N-type material within a reverse-biased setup. </span>