A prokaryotic organism is isolated from a hydrothermal vent, where it has been observed to be thriving. Based on your knowledge
1 answer:
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Answer: 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of
Explanation:
The balanced decomposition reaction is shown as
moles of
According to stoichiometry:
2 moles of gives = 3 moles of flourine gas
Thus 0.36 moles of gives =
of flourine gas
Using ideal gas equation :
P = pressure of gas = 1 atm ( at STP)
V = Volume of gas = ?
n = moles of gas = 0.54
R = gas constant = 0.0821 L atm/Kmol
T = temperature = 273 K ( at STP)
Putting the values we get :
Thus 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of
Answer:
Explanation:
The question is asking to write the <em>isotopic symbol </em>of the form for the <em>sodium isotope with 13 neutrons</em>.
In general, the isotopic symbol in the given form shows:
- The element's chemical symbol: X
- A: mass number of the isotope, written as a superscript to the left of the element's simbol, and
A = number of protons + number of neutrons
- Z: atomic number of the isotope, written as a subscript to the left of the elements's symbol,
Z = number of protons
The atomic symbol of sodium is Na.
The atomic number, or number of protons, is the same for every isotope of the element, and you can find it in any periodic table. Tha atomic number of sodium is 11. Thus:
- Z = 11
The mass number is the number of protons plus neutrons, hence:
- A = 11 + 13 = 24
Now you can write the isotope symbol for the sodium isotope with 13 neutrons:
Answer:
Explanation:
Since we aren't told the mass of material we have, let's assume the boss was generous, and precise, and we have 100.00 grams of the mystery compound. We are told only that hydrogen is 5.988% and that the only other two elements are carbon and oxygen, with equal percentages. (100%-5.988%)/2 = 47.006% of each. See the attached table.
We now have the number of grams of each element, so let's convert that into moles of each by dividing the mass by the element's molar mass, The result in the table is
<u>Moles</u>
C 3.91
H 5.99
O 2.94
We need whole numbers for the empirical formula, so round to C4H6O3, the empirical formula. Possibly acetoacetic acid, a metabolite.
