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Marina CMI [18]
2 years ago
15

Jon does an experiment in which he varies the amount of calcium chloride (CaCl2) powder used for the chemical reaction with sodi

um bicarbonate (NaHCO3). He plans to observe whether the amount of CaCl2 powder has an effect on reaction rate.
Make the most logical prediction for the results of his experiment using the drop-down menus.

I predict that using a larger amount of calcium chloride powder will
______
a. increase
b. decrease
c. have no effect on

the reaction rate because the calcium chloride molecules will ______
a. have more kinetic energy
b. balance the number of product molecules
c. collide more often with other reactant molecules
Chemistry
1 answer:
asambeis [7]2 years ago
8 0

Answer:

a.) increase

c.) collide more often with other reactant molecules

Explanation:

Generally, when you increase the quantity of reactants, the rate of the reaction increases (the forward reaction). When there are more reactants, there are more chances for them to interact with each other. More interactions means more reactions.

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How many molecules are in 68.0 g of H2S
Kryger [21]

The correct answer is 12.044 × 10²³ molecules.  

The molecular mass of H₂S is 34 gram per mole.  

Number of moles is determined by using the formula,  

Number of moles = mass/molecular mass

Given mass is 68 grams, so no of moles will be,  

68/34 = 2 moles

1 mole comprises 6.022 × 10²³ molecules, therefore, 2 moles will comprise = 6.022 × 10²³ × 2

= 12.044 × 10²³ molecules.  


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3 years ago
1. How many milliliters of 10.0 M HNO 3 are needed to prepare 0.350 L of 0.400 M solution?
tatyana61 [14]
<h3>Answer:</h3>

14 milliliters

<h3>Explanation:</h3>

We are given;

  • 10.0 M HNO₃

Prepared solution;

  • Volume of solution as 0.350 L
  • Molarity as 0.40 M

We are required to determine the initial volume of HNO₃

  • We are going to use the dilution formula;
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M₁V₁ = M₂V₂

Rearranging the formula;

V₁ = M₂V₂ ÷ M₁

    =(0.40 M × 0.350 L) ÷ 10.0 M

   = 0.014 L

But, 1 L = 1000 mL

Therefore,

Volume = 14 mL

Thus, the volume of 10.0 M HNO₃ is 14 mL

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