Answer:
- <u>option </u><u><em>B. Lose 1.</em></u>
Explanation:
To determine the number of<em> electrons that a single hydrogen gains or loses </em>you need to realize that the chemical reaction is an oxidation-reduction (redox) reaction and state the changes in the oxidation states.
The substance that gains electrons is being reduced, reducing its oxidation number, and the substance that lose electrons is being oxidized, increasing its oxidation state.
<u>1) State the oxidation state of hydrogen atoms in the rectant side:</u>
- H₂: the oxidation state of any element in its atomic or molecular form is zero. That is indicated as a superscript to the right of the chemical symbol: H₂⁰
<u>2) State the oxidation state of the hydrogen atoms in the product side:</u>
- H₂O: the rule says that the oxidation state of oxygen, when combined with other elements, except in the case of peroxides, is -2.
Hence, in order to the molecule H₂O be neutral, the total charge contributed by the two atoms of hydrogen must be + 2: +2 - 2 = 0.
Since there are two hydrogen atoms, each contributes +2 / 2 = +1 charge.
<u>3) Conclusion:</u>
Every atom of hydrogen changes from a 0 oxidation number to a +1 oxidation number, which, in turn, means that every hydrogen atom loses one electron.
Thus, the answer is, the option <em>B. Lose 1.</em>
Answer:
option c
Explanation:
Solution is formed when a solute is dissolved a solvent.
Formation of solution is decided by the interaction between solute and solvent.
When a solute is dissolved, the intermolecular interactions in between solute molecules are broken. And New interactions are formed between solute and solvent.
In order to form solution, the solute-solvent interactions must be stronger than solute-solute and solvent-solvent in interactions.
Therefore, among given the option c is correct.
Answer : The [α] for the solution is, -118.8
Explanation :
Enantiomeric excess : It is defined as the difference between the percentage major enantiomer and the percentage minor enantiomer.
Mathematically,

Given:
% major enantiomer = 86 %
% minor enantiomer = 14 %
Putting values in above equation, we get:


Now we have to calculate the [α] for the solution.
![[\alpha]=\text{Enantiomer excess}\times [\alpha]_{Pure}](https://tex.z-dn.net/?f=%5B%5Calpha%5D%3D%5Ctext%7BEnantiomer%20excess%7D%5Ctimes%20%5B%5Calpha%5D_%7BPure%7D)
![[\alpha]=0.72\times -165](https://tex.z-dn.net/?f=%5B%5Calpha%5D%3D0.72%5Ctimes%20-165)
![[\alpha]=-118.8](https://tex.z-dn.net/?f=%5B%5Calpha%5D%3D-118.8)
Thus, the [α] for the solution is, -118.8
The final volume of the unknown gas is 787.5 ml
Given:
volume of unknown gas = 450.0 mL
initial pressure of unknown gas = 0.07 atm
final pressure of unknown gas = 0.04 atm
To Find:
final volume of the unknown gas
Solution:
Substituting these values into Boyle’s law, we get
P1V1 = P2V2
(0.07)(450) = (0.04)V2
V2 = (0.07)(450)/(0.04)
V2 = 787.5
So, final volume of the unknown gas is 787.5 ml
Learn more about Volume here:
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Answer:
2NaClO₄ (aq) + Ni(NO₃)₂ (aq) → 2NaNO₃ (aq) + Ni(ClO₄)₂ (aq)
No reaction
Explanation:
NaClO₄ → Sodium perchlorate
Ni(NO₃)₂ → Nickel (II) nitrate
All the salts from nitrate are soluble salts
All the salts from perchlorate are soluble salts except for the KClO₄