Answer:
A. 0.143 M
B. 0.0523 M
Explanation:
A.
Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).
KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄
The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:
1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol
The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.
5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:
M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M
B.
Let's consider the neutralization of potassium hydroxide and perchloric acid.
KOH + HClO₄ → KClO₄ + H₂O
When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.
Answer:
The answer to your question is the first choice
Explanation:
Perishable food is food with a limited shelf life if it is not refrigerated. Also, it is considered a perishable food the one that goes bad quickly when it leaves the fridge.
Example of perishable food:
Vegetables, Fruits, Meat, Fish, Milk, Yogurt, etc.
Based on the data provided, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.
<h3>What is the moles of calcium carbonate in 1.505 × 10^23 atoms of calcium carbonate?</h3>
The mole of a substance can be calculated as follows:
- Moles of substance = number of particles/6.02 × 10^23
Moles of calcium carbonate = 1.505 × 10^23/6.02 × 10^23
Moles of calcium carbonate = 0.25 moles
The mass of calcium carbonate in 0.25 moles is calculated as follows:
- mass = moles × molar mass
molar mass of a calcium carbonate = 100 g/mol
mass of calcium carbonate = 0.25 × 100 = 25 g.
Therefore, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.
Learn more about molar mass and mass at: brainly.com/question/15476873
Answer:
B
Explanation:
The cell membrane cannot receive or recognize chemical signals
The molarity of the diluted solution is 0.33 M
From the question given above, the following data were obtained:
Molarity of stock solution (M₁) = 0. 5 M
Volume of stock solution (V₁) = 100 mL
Volume of diluted solution (V₂) = 100 + 50 = 150 mL
<h3>Molarity of diluted solution (M₂) =? </h3>
The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:
<h3>M₁V₁ = M₂V₂</h3>
0.5 × 100 = M₂ × 150
50 = M₂ × 150
Divide both side by 150
M₂ = 50 / 150
<h3>M₂ = 0.33 M</h3>
Therefore, the molarity of the diluted solution is 0.33 M
Learn more: brainly.com/question/24625656
