<u><em>Answer:</em></u>
- <em>Respect </em>
- <em>Confidentiality </em>
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<u><em>Explanation:</em></u>
<em>*Hope this helps*</em>
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Answer:
1/45 or 0.0222 g/s
Explanation:
rate of reaction = quantity of reactant used/time taken
= (10-8)/90
= 1/45 or 0.0222 g/s
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When a 10g sample of liquid water increases in temperature from 13°C to 18°C, then the amount of gained energy is 209 joules.
<h3>How do we calculate gained energy?</h3>
The amount of energy which is gained by any sample will be calculated as:
Q = mcΔT, where
Q = gained energy
m = mass of sample = 10g
c = specific heat of water = 4.18 J/g°C
ΔT = change in temperature = 18 - 13 = 5°C
On putting values we get
Q = (10)(4.18)(5)
Q = 209 Joules
Hence required amount of energy is 209 joules.
To know more about gained energy, visit the below link:
brainly.com/question/21704399