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3 years ago

An unknown solution has a pH of 2. How would you classify this solution?

1 answer:

7 0

Acidic because anything over a ph of 7 would be basic but anything below 7 would be acid and if it has a ph of 7 it would be neutral....Hope I helped

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please let me know if the answer is true or false. if false, please tell me what's false about it. the word that they are wonder

sveticcg [70]

Answer:

false the answer is woody

Explanation:

those are the two types of stems

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3 years ago

Why are gamma rays not able to reflect off a mirrors surface

ElenaW [278]

Answer:

the Ray's go right through it

Explanation:

the Ray's are so small they punch right through them

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3 years ago

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When a solution of 0.1 M Mg(NO3)2 was mixed with a limited amount of aqueous ammonia, a light white, wispy solid was observed, i

Ipatiy [6.2K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of magnesium nitrate and aqueous ammonia (ammonium hydroxide) is given as:

$Mg(NO_3)_2(aq.)+2NH_4OH(aq.)\rightarrow Mg(OH)_2(s)+2NH_4NO_3(aq.)$

A white precipitate of magnesium hydroxide is formed in the above reaction.

Ionic form of the above equation follows:

$Mg^{2+}(aq.)+2NO_3^-(aq.)+2NH_4^+(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)+2NH_4^+(aq.)+2NO_3^-(aq.)$

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Mg^{2+}(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)$

Hence, the net ionic equation is written above.

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3 years ago

Please help. Thank you guys for all your help and support. <3

miv72 [106K]

It would be “To obey the law of conservation of mass”

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3 years ago

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What are kind and number of atoms in ring portion in the haworth structure of glucose

monitta

Answer:

The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.

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3 years ago

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