Question

The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole human bodies has a field strength of 7.0 T, and the current in the solenoid is 2.0 \times 10^{2} A. What is the number of turns per meter of length of the solenoid

Answer 1

Answer:

Explanation:

Magnetic field, B = 7 T

Current , i = 2 x 100 A

let n be the number of turns per unit length.

The magnetic field due to a solenoid is given by

$B=\mu _{0}ni$

$7=4\times 31.4\times 10^{-7}\times n\times 200$

n = 27866.24 turns per metre

Answer 2

Answer:

Number of turns per unit length will be $n=2.786\times 10^4turns/m$

Explanation:

We have given that strength of the magnetic field produced by the solenoid B = 7 T

Current in the solenoid i = 200 A

Let the number of turns per unit length is n

Magnetic field due to solenoid is given as $B=\mu ni$ here $\mu$ is permeability of free space n is number of turns per unit length and i is current

So $7=4\pi \times 10^{-7}\times n\times 200$

$n=2.786\times 10^4turns/m$