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bulgar [2K]
3 years ago
15

During a total lunar eclipse, the moon remains visible because ________.

Physics
1 answer:
Semmy [17]3 years ago
3 0

During a total lunar eclipse, the Moon is still visible to the naked eye due to the fact that the atmosphere of our planet, which is Earth bends, which results to the scattering of some sunlight, which actually reaches the Moon during a Lunar Eclipse, which is why the Moon remains visible despite the occurrence of a full lunar eclipse.

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All waves transmit?
PtichkaEL [24]

Answer:

The transmission of energy is one thing that is carried out by all kinds of waves. They transmit energy from one point, known as the source, to another point.

For instance, in electromagnetic waves, energy is transmitted as a result of vibrations between the magnetic field and electric field. In mechanical waves, energy is transmitted when the particles in the medium heat up and vibrate. Energy travels through particles in a medium.

3 0
3 years ago
Matter with no definite volume and no definite shape is a ____.
Andrews [41]

Answer:

It is gas. Gas does not consist of definite volume or shape since it is just air but in the form of gas, if this helped then please mark brainliest. Have a nice day.

4 0
3 years ago
Why is it good idea for carriers for disease genes to get tested before having children?
Leni [432]
It is good idea to see if the disease genes carriers will pass disease to children
7 0
3 years ago
ptsA flashlight is pointed at the ground, forming a spot of light. The radius of the spot of light is measured and the area of t
agasfer [191]

Answer:

I₂ = I₀  1/4

Explanation:

For this exercise we use the definition of intensity which is the power per unit area

         I = P / A

The emitted power is constant, so

     P = I A

We can write this equation for the start and end point with index 2

    I₀ A₀ = I₂ A₂

    I₂ = I₀ A₀ / A₂

The spot area is the area of ​​the circle

      A₀ = π r₀²

We substitute

     I₂ = I₀ r₀² / r₂²

It indicates that the radius of the spot is twice the initial radius

      r₂ = 2 r₀

      I₂ = I₀ (r₀ / 2 r₀)²

      I₂ = I₀  1/4

7 0
3 years ago
Two identical conducting spheres carry charges of +5.0 μC and –1.0 μC, respectively. The centers of the spheres are initially se
Dovator [93]

Answer:

B) 4/5

Explanation:

The magnitude of the electric force between the two spheres is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulombs' constant

q1 and q2 are the charges on the two spheres

r is the distance between the two spheres

Initially, we have

q_1 = 5.0\mu C=5.0\cdot 10^{-6}C\\q_2 = 1.0 \mu C=1.0 \cdot 10^{-6}C\\r = L

So the force is

F_1=k\frac{(5.0\cdot 10^{-6}C)(1.0\cdot 10^{-6}C)}{L^2}=(5.0 \cdot 10^{-12} C^2)\frac{k}{L^2}

Later, the two spheres are brought together so they are in contact: this means that the total charge will redistribute equally on the two spheres (because they are identical).

The total charge is

Q=q_1 + q_2 = +4.0 \mu C=4.0\cdot 10^{-6}C

So each sphere will have a charge of

q=\frac{Q}{2}=2.0\cdot 10^{-6} C

So, the new force will be

F_2=k\frac{(2.0\cdot 10^{-6}C)(120\cdot 10^{-6}C)}{L^2}=(4.0 \cdot 10^{-12} C^2)\frac{k}{L^2}

And so the ratio of the two forces is

\frac{F_2}{F_1}=\frac{4.0\cdot 10^{-12} C}{5.0\cdot 10^{-12} C}=\frac{4}{5}

8 0
3 years ago
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