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Zina [86]
3 years ago
10

ptsA flashlight is pointed at the ground, forming a spot of light. The radius of the spot of light is measured and the area of t

he spot is calculated. The brightness of the spot is measured. Then the flashlight is moved so it is twice as far from the floor.The new brightness will be ________ times the old brightness.
Physics
1 answer:
agasfer [191]3 years ago
7 0

Answer:

I₂ = I₀  1/4

Explanation:

For this exercise we use the definition of intensity which is the power per unit area

         I = P / A

The emitted power is constant, so

     P = I A

We can write this equation for the start and end point with index 2

    I₀ A₀ = I₂ A₂

    I₂ = I₀ A₀ / A₂

The spot area is the area of ​​the circle

      A₀ = π r₀²

We substitute

     I₂ = I₀ r₀² / r₂²

It indicates that the radius of the spot is twice the initial radius

      r₂ = 2 r₀

      I₂ = I₀ (r₀ / 2 r₀)²

      I₂ = I₀  1/4

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