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Nataly_w [17]
3 years ago
13

Why do organisms need nitrogen

Physics
1 answer:
Yuri [45]3 years ago
4 0
Plants and animals need nitrogen in order to make proteins. Proteins are essential compounds for healthy growth and fully functioning organisms.
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At the top of a giant swing on the gymnastics high bar, candy's velocity is 1 m/s, and she is 3.5 m high. if candy's mass is 50
Allushta [10]
The total mechanical energy is the sum of the kinetic energy and the gravitational potential energy:
E=K+U= \frac{1}{2}mv^2 +mgh
where m=3.5 kg is Candy's mass, v=1 m/s is her velocity and h=3.5 m is her height. If we replace these numbers, we find the mechanical energy of the system:
E= \frac{1}{2} (50 kg)(1m/s)^2 + (50 kg)(9.81 m/s^2)(3.5 m)=1742 J =1.74 kJ
6 0
3 years ago
which of the numbers on this figure indicates typical continental conditions (regional metamorphism)?
Tpy6a [65]

The number that indicates typical continental conditions (regional metamorphism) is that showing schist and gneiss rocks.

<h3>What is regional metamorphism?</h3>

Regional metamorphism occurs when rocks undergoes changes as a result of high temperatures and pressure deep within the earth's crust.

Regional metamorphic rocks are usually foliated or squashed in appearance.

Examples of regional metamorphism rocks are schist and gneiss rocks.

Therefore, the figure that indicates typical continental conditions (regional metamorphism) is that showing schist and gneiss rocks.

Learn more about regional metamorphism at: brainly.com/question/14678538

#SPJ11

4 0
2 years ago
Read 2 more answers
6. If two objects each have a mass of 10 kg, then the force of gravity between them
frozen [14]

Answer:

3

Explanation:

Answer is what its supposed to be. lol.

Stick with it brother. You GOT THIS!!! 100%

b.

8 0
2 years ago
Consider a steel guitar string of initial length L=1.00 meter and cross-sectional area A=0.500 square millimeters. The Young's m
Reil [10]

Answer:

\Delta l=0.015m

Explanation:

We have given initial length of the steel guitar l = 1 m

Cross sectional area A=0.5mm^2=0.5\times 10^{-6}m^2

Young's modulus \gamma=2\times 10^{11}Pa

Force F = 1500 N

So stress =\frac{force}{area}=\frac{1500}{0.5\times 10^{-6}}=3000\times 10^{-6}=3\times 10^{9}Pa

We know that young's modulus =\frac{stress}{strain}

So 2\times 10^{11}=\frac{3\times 10^{9}}{strain}

strain=1.5\times 10^{-2}=0.015m

Now strain =\frac{\Delta l}{l}

0.015=\frac{\Delta l}{1}

\Delta l=0.015m

6 0
3 years ago
Read 2 more answers
A circuit with two or more branches for current to flow
Natalija [7]

If there's any point in a circuit where the current has a choice
of which branch to take, then you have a <em>parallel circuit</em>.


4 0
3 years ago
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