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marshall27 [118]
3 years ago
5

In elastic collisions,total kinetic energy and momentum are both conserved. On a frictionless track,cart 1 is moving with a cons

tant,rightward(+) velocity of 1.0m/s.Cart 2 is also moving rightward with constant velocity of 5.0m/s. After a while,cart 2 collides cart 1 from behind.(It is an elactic collision.)If the final velocity of cart 2 becomes 3.0m/s, what is the final velocity of cart 1?(SHOW ALL YOUR WORK.)
Physics
1 answer:
kari74 [83]3 years ago
5 0

Answer:

Explanation:

mass of cart 1, m1 = m

mass of cart 2, m2 = m

initial velocity of cart 1, u1 = 1 m/s

initial velocity of cart 2, u2 = 5 m/s

final velocity of cart 2, v2 = 3 m/s  

Let the final velocity of cart 1 is v1.

Use the conservation of momentum

m1 x u1 + m2 x u2 = m1 x v1 + m2 x v2

m x 1 + m x 5 = m x v1 + m x 3

6 = v1 + 3

v1 = 3 m/s

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Answer:

Tech B is correct and Tech A is incorrect.

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2. Name two specific contributions Bohr made to our understanding of atomic
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Explanation:

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_____ is very corrosive and can cause rusting so metal tanks shouldn't be used
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A steel ball of mass 0.500 kg is fastened to a cord that is 70.0 cm long and fixed at the far end. The ball is then released whe
Liula [17]

Answer:

a) v₁fin = 3.7059 m/s   (→)

b) v₂fin = 1.0588 m/s     (→)

Explanation:

a) Given

m₁ = 0.5 Kg

L = 70 cm = 0.7 m

v₁in = 0 m/s   ⇒  Kin = 0 J

v₁fin = ?

h<em>in </em>= L = 0.7 m

h<em>fin </em>= 0 m   ⇒    U<em>fin</em> = 0 J

The speed of the ball before the collision can be obtained as follows

Einitial = Efinal

⇒ Kin + Uin = Kfin + Ufin

⇒ 0 + m*g*h<em>in</em> = 0.5*m*v₁fin² + 0

⇒ v₁fin = √(2*g*h<em>in</em>) = √(2*(9.81 m/s²)*(0.70 m))

⇒ v₁fin = 3.7059 m/s   (→)

b)  Given

m₁ = 0.5 Kg

m₂ = 3.0 Kg

v₁ = 3.7059 m/s    (→)

v₂ = 0 m/s

v₂fin = ?

The speed of the block just after the collision can be obtained using the equation

v₂fin = 2*m₁*v₁ / (m₁ + m₂)

⇒  v₂fin = (2*0.5 Kg*3.7059 m/s) / (0.5 Kg + 3.0 Kg)

⇒  v₂fin = 1.0588 m/s     (→)

7 0
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Question 7 of 10
nevsk [136]

Answer:

a

Explanation:

you take 32,000kg ÷2.0m

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