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dlinn [17]
3 years ago
7

What is your zodiac sign?

Physics
1 answer:
ahrayia [7]3 years ago
7 0
Answer: Gemini

Explanation: lol I just born that that sign ig
You might be interested in
What kind of motion do you see when using scissors
Novay_Z [31]

Answer:

When we are using scissors, our hand makes an open and close motion.

Explanation:

3 0
3 years ago
Read 2 more answers
A block of mass 0.490 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x. T
Dennis_Churaev [7]

Answer:

The value of x is  x = 0.1955\ m

The value of the velocity at the top is  v_{top} = 2.25 \ m/s

Explanation:

The diagram of this process is on the first uploaded image

From the question we are told that

     The mass of the block is m_b = 0.490kg

      The distance of compression is x

      The force constant is k = 450 N/m

      The radius of the circular track is R =1.00m

       The speed at the bottom of the track is v_A = 13.4 \ m/s

        The frictional force experienced is F_f = 7.00 \ N

Now looking at this process we see that the potential energy of the spring is been transformed into the kinetic energy  of the block . So,

          PE \ of \ spring = KE \ of  \ block

mathematically i.e

        \frac{1}{2}k x^2  = \frac{1}{2} m_bv^2_A

       0.5 * 450 * x^2 = 0.5 * 0.490 * 13.4^2

Making x the subject of the formula

           x = \sqrt{\frac{0.5 * 0.490 * 13.4^2}{ 0.5 * 450} }

              = 0.1955\ m

The average workdone by friction is  W_f = F_f * \pi

Here \pi is \ the\  net\ displacement

                                         W_f = 7 * 3.142

                                               = 21.99 J

The kinetic energy at the bottom is

                                     KE = \frac{1}{2} * 0.490 * 13.4^2

                                            = 43.99 \ N

The potential energy gained at the top of the circle is

                              PE = m_bgh

Here h  is the height which is equal to d(diameter)  = 2r = 2 × 1 = 2 m and

g is acceleration due to gravity = 9.8m/s^2

Now substituting values

                       PE = 0.490 * 9.8 *2

                             =9.604 J

Since energy is can not be created nor destroyed but transformed  according to first law of thermodynamics

                  KE_{at \bottom} = PE _ {\ at \ top } + W_f + KE_{\ at \ top}

                      43.99 = 9.604 +21.99 + [\frac{1}{2} m_b * v_{top} ^2]

                        12.369= [2.45* v_{top} ^2]

                            v_{top} =\sqrt{\frac{12.369}{2.45} }

                                  = 2.25 \ m/s

                                     

                                 

8 0
3 years ago
Why does the Moon seem to change shape?
Licemer1 [7]

Answer:

A

Explanation:

3 0
3 years ago
Read 2 more answers
When this current is closed which way does the current flow
Anastaziya [24]
Well, Godess, that's not a simple question, and it doesn't have
a simple answer.

When the switch is closed . . .

"Conventional current" flows out of the ' + ' of the battery, through R₁ ,
then through R₂ , then through R₃ .  It piles up on the right-hand side of
the capacitor (C).  It repels the ' + ' charges on the left side of 'C', and
those flow into the ' - ' side of the battery.  So the flow of current through
this series circuit is completely clockwise, around toward the right. 

That's the way the first experimenters pictured it, that's the way we still
handle it on paper, and that's the way our ammeters display it.

BUT . . .

About 100 years after we thought that we completely understand electricity,
we discovered that the little tiny things that really move through a wire, and
really carry the electric charge, are the electrons, and they carry NEGATIVE
charge.  This turned our whole picture upside down.

But we never changed the picture !  We still do all of our work in terms of
'conventional current'.  But the PHYSICAL current ... the actual motion of
charge in the wire ... is all exactly the other way around.

In your drawing ... When the switch is closed, electrons flow out of the 
' - ' terminal on the bottom of the battery, and pile up on the left plate of
the 'C'.  They repel electrons off of the right-side of 'C', and those then
flow through R₃ , then through R₂ , then through R₁ , and finally into the
' + ' terminal on top of the battery.

Those are the directions of 'conventional' current and 'physical' current
in all circuits.

In the circuit of YOUR picture that you attached, there's more to the story:

Battery current can't flow through a capacitor.  Current flows only until
charges are piled up on the two sides of 'C' facing each other, and then
it stops.

Wait a few seconds after you close the switch in the picture, and there is
no longer any current in the loop.

To be very specific and technical about it . . .

-- The instant you close the switch, the current is

       (battery voltage) / (R₁ + R₂ + R₃)        amperes

but it immediately starts to decrease.

--  Every  (C)/((R₁ + R₂ + R₃)  seconds after that, the current is

                  e⁻¹  =  about  36.8 %

less than it was that same amount of time ago.

Now, are you glad you asked ?
4 0
3 years ago
True or false kinetic energy is the energy of a moving tennis ball
Kay [80]

answer = true

reasoning

kinetic energy is the energy of movement

potential energy is built up kinetic energy

hope this helps!


5 0
3 years ago
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