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tino4ka555 [31]
3 years ago
6

The 300 m diameter Arecibo radio telescope is observing the Andromeda galaxy at a wavelength of 29 cm. show answer No Attempt 50

% Part (a) What is the angle between two just-resolvable stars for this telescope in radians
Physics
1 answer:
jekas [21]3 years ago
3 0

Answer:

The angle between two just-resolvable stars for the Arecibo telescope is 1.179x10^{-3}rad.

Explanation:

The resulting image in a telescope obtained from an object is a diffraction pattern.

That diffraction pattern is obtained because the light encounters different obstacles on its path inside the telescope (interact with the walls and edges of the instrument).

The diffraction pattern is composed by a central disk, called Airy disk, and diffraction rings.    

 

The angular resolution is defined as the minimal separation at which two sources can be resolved one for another, or in other words, when the distance between the two diffraction patterns maxima is greater than the radius of the Airy disk.

The angular resolution can be determined in an analytical way by means of the Rayleigh criterion.          

\theta = 1.22\frac{\lambda}{D}   (1)

Where \lambda is the wavelength and D is the diameter of the telescope.

Notice that it is necessary to express the wavelength in the same units than the diameter.

\lambda = 29cm \cdot \frac{1m}{100cm} ⇒ 0.29m

Finally, equation 1 can be used.

\theta = 1.22(\frac{0.29m}{300m})

\theta = 1.179x10^{-3}rad              

Hence, the angle between two just-resolvable stars for the Arecibo telescope is 1.179x10^{-3}rad    

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Answer

613.63Hz

Explanation:

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Fobs= (343/343-18.8)580

Fobs= 613.63Hz

Fobs = frequency observed

brainly.com/question/15339151

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2 years ago
Two charges q1 and q2, that are distance d apart , repel each other with a force of 6.40 N. what would be the force between two
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Q: Two charges q1 and q2, that are distance d apart , repel each other with a force of 6.40 N. what would be the force between two charges q1'=2q1 and q2'=3q2 that that are distance d apart?

Answer:

The force = 38.4 N

Explanation:

From coulombs law,

F = kq₁q₂/r² ............................ Equation 1

Where F = Force of attraction or repulsion between the charges, q₁ and q₂ = first and second charge respectively, r = distance between the charges, k = constant of proportionality.

When, F = 6.4 N, r = d m.

6.4 = kq₁q₂/d²......................... Equation 1

When q₁' = 2q₁, q₂' = 3q₂, r = d cm

F = k(2q₁)(3q₂)/d²

F = 6kq₁q₂/d².......................... Equation 2

Dividing Equation 1 by equation 2

6.4/F = kq₁q₂/d²/(6kq₁q₂/d²)

6.4/F = 1/6

F = 6.4×6

F = 38.4 N.

Thus the force = 38.4 N

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Hope this helps


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