Let both the balls have the same mass equals to m.
Let 
and 
be the speed of the ball1 and the ball2 respectively, such that
Assuming that both the balls are at the same level with respect to the ground, so let h be the height from the ground.
The total energy of ball1= Kinetic energy of ball1 + Potential energy of ball1. The Kinetic energy of any object moving with speed, 
, is 
and the potential energy is due to the change in height is 
[where 
is the acceleration due to gravity]
So, the total energy of ball1,
and the total energy of ball1,
.
Here, the potential energy for both the balls are the same, but the kinetic energy of the ball1 is higher the ball2 as the ball1 have the higher speed, refer equation (i)
So, 
Now, from equations (ii) and (iii)
The total energy of ball1 hi higher than the total energy of ball2.
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Answer:
W = 222 N.
Explanation:
The qiestion says" If the acceleration of gravity on the surface of the planet Mercury is 3.7 m / s2, then what would be the weight of a person with mass 60 kg on its surface?
"
Mass of the person, m = 60 kg
The acceleration due to gravity on the surface of gravity is 3.7 m/s²
We need to find the weight of a person on the surface of Mercury.
Weight of an object is given by :
W = mg
So,
W = 60 kg × 3.7 m/s²
W = 222 N
Hence, the person will weigh 2222 N on the surface of Moon.
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