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Anettt [7]
3 years ago
8

As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.01 mm apart and position

your screen 3.65 m from the slits. Although Young had to struggle to achieve a monochromatic light beam of sufficient intensity, you simply turn on a laser with a wavelength of 641 nm . How far on the screen are the first bright fringe and the second dark fringe from the central bright fringe? Express your answers in millimeters.
Physics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

2.316e-3 and 3.47e-3

Explanation:

Now, at that angle, we look at the bright spots on the screen.

tan θ = x / L (x is the horizontal distance from the centre of the screen, L is distance to screen)

For small angles, we can approximate that tan θ = sin θ.

nλ / d = x / L         so then       x = n λ L / d

First bright fringe, n = 1

x = (1) (641*10^-9 m) (3.65 m) / (1.01*10^-3 m) = 2.316e-3

For destructive interference (dark fringes), equation becomes:

x = (n - 0.5) λ L / d

Second dark fringe, n = 1.5

x = 1.5 (641*10^-9 m) (3.65 m) / (1.01*10^-3 m) = 3.47e-3

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The force of gravity pulls down on your school with a total force of 400,000 newtons. The force of gravity pulling down on your
gizmo_the_mogwai [7]

Answer: a Had twice as much mass

Explanation:

The data that we have is:

"The force of gravity pulls down on your school with a total force of 400,000 newtons. "

First, remember that, by the second Newton's law that:

F = a*m

F = force

a = acceleration

m = mass

In the case of the gravitational force, the gravitational acceleration is a constant: a = 9.8m/s^2

Then, if we want to have twice as much force the only thing that we can change in the equation is the mass:

Then if the initial force is written as:

F = a*m

twice as much that force is written as:

2*F = a*x

x is a variable that represents the new mass.

We know that F = a*m

2*F = 2*a*m

2*a*m  = a*x

2*m = x

Then, if we want to have twice as much force, we should have twice as much mass.

7 0
3 years ago
On the moon, a feather is dropped from a height of 1.40 m. The acceleration of gravity on the moon is -1.67 m/s2. Determine the
Molodets [167]

Answer:

1.29 s

Explanation:

  • Height = 1.40m
  • Acclⁿ due to gravity = 1.67 m/s²
  • Time of descent = ?

As we know that ,

\sf\longrightarrow Time_{descent}= \sqrt{\dfrac{2H}{g_{(moon)}}}\\\\\sf\longrightarrow t_d = \sqrt{\dfrac{ 2\times 1.4}{1.67}} \\\\\sf\longrightarrow t_d =\sqrt{1.67} s\\\\\sf\longrightarrow \boxed{\red{\sf Time_{descent}= 1.29 s }}

4 0
3 years ago
While Robert was helping his father in the garden, he pushed a shovel into the ground to dig a hole in the dirt. He picked up a
makvit [3.9K]

Work done is given by the change in kinetic energy of an object

  • The kinetic energy of the shovel, the shrub, and in Robert's movement were changed, therefore, work is done in the given processes,

Reason:

Work is done when the total energy of object is affected by the application of force on the object over a distance

Therefore;

  • In option <em>A</em>, pushing the shovel into ground (to dig out the dirt) the requires the application of a force (push) over a distance, (into and out of the ground) therefore work is done
  • In option <em>B</em>, picking the shrub up gives it gravitational potential energy, therefore, work is done
  • In option <em>C</em>, carrying the shrub to the hole does visible work
  • In option <em>D</em>, holding the shrub while lowering it into the hole does work by preventing the shrub from falling randomly

Therefore, <u>work is done in the given processes</u>

Learn more about work-energy theorem here:

brainly.com/question/10063455

7 0
3 years ago
A bowling ball of mass 4 kg moves in a straight line at 3.93 m/s. How fast must a Ping-Pong ball of mass 2.293 g move in a strai
Nonamiya [84]

M = mass of the bowling ball = 4 kg

V = speed of bowling ball = 3.93 m/s

P = magnitude of momentum of bowling ball = ?

magnitude of momentum of bowling ball is given as

P = MV

inserting the values

P = 4 x 3.93

P = 15.72 kgm/s

m = mass of ping-pong ball = 2.293 g = 2.293 x 10⁻³ kg

v = speed of the ping-pong ball = ?

p = magnitude of momentum of ping-pong ball

Given that :

magnitude of momentum of ping-pong ball  =  magnitude of momentum of bowling ball

p = P

m v = 15.72

(2.293 x 10⁻³) v = 15.72

v = 6.86 x 10³ m/s


4 0
3 years ago
A 0.300 kg mass is attached to
scoundrel [369]

Answer:

0.144 J

Explanation:

From the question above,

Total elastic energy of the spring = Kinetic energy of the spring + potential energy of the spring

E' = E.k+Ep...................... Equation 1

Ek = E'-Ep......................... Equation 2

Where E' = total elastic energy, E.k = kinetic energy, E.p = potential  energy.

E'  = 1/2ke² = 1/2(26.6)(0.12²) = 0.19152 J.

Ep = 1/2ke² = 1/2(26.6)(0.06²)

Ep = 0.04788 J

Therefore,

Ek = 0.19152-0.04788

Ek = 0.144 J

8 0
3 years ago
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