Answer: a Had twice as much mass
Explanation:
The data that we have is:
"The force of gravity pulls down on your school with a total force of 400,000 newtons. "
First, remember that, by the second Newton's law that:
F = a*m
F = force
a = acceleration
m = mass
In the case of the gravitational force, the gravitational acceleration is a constant: a = 9.8m/s^2
Then, if we want to have twice as much force the only thing that we can change in the equation is the mass:
Then if the initial force is written as:
F = a*m
twice as much that force is written as:
2*F = a*x
x is a variable that represents the new mass.
We know that F = a*m
2*F = 2*a*m
2*a*m = a*x
2*m = x
Then, if we want to have twice as much force, we should have twice as much mass.
Work done is given by the change in kinetic energy of an object
- The kinetic energy of the shovel, the shrub, and in Robert's movement were changed, therefore, work is done in the given processes,
Reason:
Work is done when the total energy of object is affected by the application of force on the object over a distance
Therefore;
- In option <em>A</em>, pushing the shovel into ground (to dig out the dirt) the requires the application of a force (push) over a distance, (into and out of the ground) therefore work is done
- In option <em>B</em>, picking the shrub up gives it gravitational potential energy, therefore, work is done
- In option <em>C</em>, carrying the shrub to the hole does visible work
- In option <em>D</em>, holding the shrub while lowering it into the hole does work by preventing the shrub from falling randomly
Therefore, <u>work is done in the given processes</u>
Learn more about work-energy theorem here:
brainly.com/question/10063455
M = mass of the bowling ball = 4 kg
V = speed of bowling ball = 3.93 m/s
P = magnitude of momentum of bowling ball = ?
magnitude of momentum of bowling ball is given as
P = MV
inserting the values
P = 4 x 3.93
P = 15.72 kgm/s
m = mass of ping-pong ball = 2.293 g = 2.293 x 10⁻³ kg
v = speed of the ping-pong ball = ?
p = magnitude of momentum of ping-pong ball
Given that :
magnitude of momentum of ping-pong ball = magnitude of momentum of bowling ball
p = P
m v = 15.72
(2.293 x 10⁻³) v = 15.72
v = 6.86 x 10³ m/s
Answer:
0.144 J
Explanation:
From the question above,
Total elastic energy of the spring = Kinetic energy of the spring + potential energy of the spring
E' = E.k+Ep...................... Equation 1
Ek = E'-Ep......................... Equation 2
Where E' = total elastic energy, E.k = kinetic energy, E.p = potential energy.
E' = 1/2ke² = 1/2(26.6)(0.12²) = 0.19152 J.
Ep = 1/2ke² = 1/2(26.6)(0.06²)
Ep = 0.04788 J
Therefore,
Ek = 0.19152-0.04788
Ek = 0.144 J