Answer:
The wire now has less (the half resistance) than before.
Explanation:
The resistance in a wire is calculated as:
Were:
R is resistance
is the resistance coefficient
l is the length of the material
s is the area of the transversal wire, in the case of wire will be circular area ().
So if the lenght and radius are doubled, the equation goes as follows:
So finally because the circular area is a square function, the resulting equation is half of the one before.
Answer:
Explanation:
For this case the situation is explained in the figure attached.
We can find the maximum radius r with the angle of incidence or critical angle (xi). If we have that the angle is higher than the light we will see a reflecting property. We can assume that the refracted angle for this case is 90 and if we use the following trigonometric property we have:
And if we solve for r we got:
The value of d on this case represent the depth of the watr d = 2.5 m
And we can find the value for the angle using the Snell's Law like this:
And we can use the arcsin in order to find the angle like this:
And now we can find the maximum radius replacing into
And we got:
Answer:
The gauge pressure is equal to 147 kPa.
Explanation:
The pressure exerted by fluid is given by :
Where
is density of water
h is height
So, put all the values,
or
P = 147 kPa
So, the gauge pressure is equal to 147 kPa.