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slava [35]
3 years ago
15

A tumbleweed is moving with a velocity of 5.4 m/s westward. A sudden gust of wind blows for 1.5 seconds and reduces its velocity

to 1.8 m/s. What is the acceleration of the tumbleweed during this time
Physics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer:

a=-2.4 m/s^{2}

Explanation:

Let's recall the acceleration definition.

a=\frac{\Delta v}{\Delta t} (1)

Δv is the velocity variation, Δv = v(f) - v(i). It is just the difference between final and initial velocities. So Δv = 1.8[m/s] - 5.4[m/s] = -3.6 [m/s]

And Δt is the time variation, in this case it is just 1.5 s.

Therefore, using the equation (1), the acceleration will be:

a=\frac{-3.6}{1.5}=-2.4 m/s^{2}

The minus sign means that the tumbleweed is slowing down.

I hope it helps you!

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si comparamos la gota de agua cayendo en una gotera, y el sonido del agua hirviendo,ambos con la misma intensidad ¿cuál sonido t
mrs_skeptik [129]

Answer:

ambas

Explanation:

Tendrían el mismo sonido ya que la intensidad es la misma.

8 0
3 years ago
suppose you want to determine the surface area of this sugar cube. it has edges that are each 2 cm long. if you cut the cube in
ivolga24 [154]

Answer:

Half: 6 cm^2    Whole: 12 cm^2

Explanation:

First, we know that the edges of the cube are 2 cm long. So there are 6 faces on a cube. We do 2x6=12 cm^2 as our total surface area. Then it asks for each half. So you would divide it by 2 and get 6 cm^2 as your half.

5 0
3 years ago
A billiards ball B rests on a horizontal surface and is struck by another billiards ball A of the same mass m = 0.2 kg. Ball A i
SOVA2 [1]

Answer:

v1 = 15.90 m/s

v2 = 8.46 m/s

mechanical energy before collision = 32.4 J

mechanical energy after collision = 32.433 J

Explanation:

given data

mass m = 0.2 kg

speed = 18 m/s

angle =  28°

to find out

final velocity and  mechanical energy both before and after the collision

solution

we know that conservation of momentum remain same so in x direction

mv = mv1 cosθ + mv2cosθ

put here value

0.2(18) = 0.2 v1 cos(28) + 0.2 v2 cos(90-28)

3.6 =  0.1765 V1 + 0.09389 v2    ................1

and

in y axis

mv = mv1 sinθ - mv2sinθ

0 = 0.2 v1 sin28 - 0.2 v2 sin(90-28)

0 = 0.09389 v1 - 0.1768 v2   .......................2

from equation 1 and 2

v1 = 15.90 m/s

v2 = 8.46 m/s

so

mechanical energy  before collision = 1/2 mv1² + 1/2 mv2²

mechanical energy before collision = 1/2 (0.2)(18)² + 0

mechanical energy before collision = 32.4 J

and

mechanical energy after collision = 1/2 (0.2)(15.90)² + 1/2 (0.2)(8.46)²

mechanical energy after collision = 32.433 J

7 0
3 years ago
For two objects with masses 100 kg and 500 kg to be 20 meters apart , find the gravity between them
Vikki [24]

Answer:

8,3375*10^-9 N

Explanation:

4 0
3 years ago
Density=2g/mL and volume=20mL what is mass
leva [86]

Answer:

40g

Explanation:

Mass = density x volume

= 2 x 20

= 40g

8 0
3 years ago
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