All categories

4 years ago

PLEASE HELP, LOOK AT PHOTO PLZ!!!

Physics

1 answer:

PIT_PIT [208]4 years ago

3 0

Answer:

a) 17 km

b) 9 km

Explanation:

The distance is the length of the path.

A to C: 5 km

B to C: 4 km

C to B: 4 km

B to C: 4 km

Total distance = 5 km + 4 km + 4 km + 4 km = 17 km

Displacement is the difference between the starting point and ending point.

Displacement = 9 km − 0 km = 9 km

You might be interested in

In an experiment, the 1 kg cart collides with a 3 kg cart but doesn’t stick to it. Instead, the 3 kg cart gets knock forward by

notka56 [123]

Explanation:

Given that,

Mass of the cart, $m_1=1\ kg$

Mass of the cart 2, $m_2=3\ kg$

Final speed of cart 2, $v_2=0.3\ m/s$

Final speed of cart 1 is 0 as it comes to rest.

Let us assume that the initial velocity of the cart 2 is 0. So using the conservation of linear momentum as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\m_1u_1+0=0+m_2v_2\\\\m_1u_1=m_2v_2\\\\u_1=\dfrac{m_2v_2}{m_1}\\\\u_1=\dfrac{3\times 0.3}{1}\\\\u_1=0.9\ m/s$

So, the initial velocity of the 1.0-kg cart is 0.9 m/s.

8 0

3 years ago

When enough energy is produced to a gas the electrons on the gaseous atoms being to detach themselves leaving ions of the typica

Luba_88 [7]

Answer:

it's called ionization

4 0

3 years ago

A 290 gg bird flying along at 6.2 m/sm/s sees a 9.0 gg insect heading straight toward it with a speed of 34 m/sm/s (as measured

Murrr4er [49]

Answer:

The bird's speed immediately after swallowing is 4.98 m/s.

Explanation:

Given that,

Mass of bird = 290 g

Speed = 6.2 m/s

Mass of sees = 9.0 g

Speed = 34 m/s

We need to calculate the bird's speed immediately after swallowing

Using conservation of momentum

$m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{3}$

Put the value into the formula

$0.290\times6.2+0.009\times(-34)=(0.290+0.009)\times v_{3}$

$v_{3}=\dfrac{0.290\times6.2-0.009\times34}{(0.290+0.009)}$

$v_{3}=4.98\ m/s$

Hence, The bird's speed immediately after swallowing is 4.98 m/s.

6 0

3 years ago

A horse does 910 J of work in 380 seconds while pulling a wagon. What is the power output of the horse? Round your answer to two

frutty [35]

Answer: 2.4 watts

Explanation:

Work done by horse = 910J

Time = 380 seconds

Power output of the horse = ?

Recall that power is the rate of doing work. Thus, power is workdone divided by time taken.

i.e Power = (work/time)

Power = 910J/380seconds

Power = 2.395 watts (rounded to two significant figures as 2.4 watts)

Thus, the power output of the horse is 2.4 watts

7 0

3 years ago

What is the purpose of the three R’s of resource management?

Natalka [10]

The answer is A sorry i would of expalined why but i have to go :c

8 0

4 years ago

Read 2 more answers