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musickatia [10]
3 years ago
6

Suppose an electrical wire is replaced with one having every linear dimension doubled (i.e. the length and radius have twice the

ri original values). The wire now has ... a resistance which depends only on the material. the same resistance as before. less resistance than before. a resistance which can't be further predicted with the given information. more resistance than before.
Physics
1 answer:
saul85 [17]3 years ago
7 0

Answer:

The wire now has less (the half resistance) than before.

Explanation:

The resistance in a wire is calculated as:

R=\alpha \frac{l}{s}

Were:

R is resistance

\alpha is the resistance coefficient

l is the length of the material

s is the area of the transversal wire, in the case of wire will be circular area (s=\pi r^{2}).

So if the lenght and radius are doubled, the equation goes as follows:

R=\alpha \frac{l}{\pi r^{2} } =\alpha \frac{2l}{\pi {(2r)}^{2} } =\alpha \frac{2l}{\pi 4 {r}^{2} }=\frac{1}{2} \alpha \frac{l}{\pi r^{2} }

So finally because the circular area is a square function, the resulting equation is half of the one before.

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Newtons first law 1 to 5. <br>What is each of the net force for all of the 5 questions? ​
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Answer:

1. 65 N.

2. 160 N.

3. 0 N.

4. 210 N.

5. 90 N.

Explanation:

1. Determination of the net force.

Force applied to the right (Fᵣ) = 80 N

Force applied to the left (Fₗ) = 145 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 145 – 80

Fₙ = 65 N

Thus, the net force is 65 N

2. Determination of the net force.

Force 1 applied to the left (F₁) = 35 N

Force 2 applied to the left (F₂) = 125 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 35 + 125

Fₙ = 160 N

Thus, the net force is 160 N.

3. Determination of the net force.

Force applied to the right (Fᵣ) = 75 N

Force applied to the left (Fₗ) = 75 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 75 – 75

Fₙ = 0

Thus, the net force is 0 N

4. Determination of the net force.

Force 1 applied to the right (F₁) = 150 N

Force 2 applied to the right (F₂) = 60 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 150 + 60

Fₙ = 210 N

Thus, the net force is 210 N.

5. Determination of the net force.

Force applied to the right (Fᵣ) = 115 N

Force applied to the left (Fₗ) = 25 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 115 – 25

Fₙ = 90 N

Thus, the net force is 90 N

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when charges mutually repel and distribute themselves on the surface of conductors, what becomes of the electric field inside th
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The charges align themselves so that the conductor's internal field is zero.

<h3>What occurs if a charged surface is in close proximity to a conducting surface?</h3>

Induced charges are created on the conductor when a charge is brought close to it. The internal free charges of the conductor, however, are gathered throughout its surface because the electric field inside the conductor must be zero in order to defeat the electric field of induced charges.

<h3>What takes place within a conductor?</h3>

A substance that has a lot of free electrons accessible for the flow of current is said to be a conductor. Since there are numerous electrons, a powerful force of repulsion exists between them as well. As a result, the electrons move to lessen their attraction for one another.

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