Answer:
Maria
Explanation:
The gravity of the earth is so strong it causes the magnetic pull of anything and everything, this causing the ball to be dropped and pulled towards earth
The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.
Molar mass of the unknown compound = 223.94 g/mol (given)
Mass of each element present in the unknown compound is determined as:
- Mass of carbon,
:

- Mass of hydrogen,
:

- Mass of chlorine,
:

Now, the number of each element in the unknown compound is determined by the formula:

- Number of moles of
:

- Number of moles of
:

- Number of moles of


Dividing each mole with the smallest number of mole, to determine the empirical formula:


Multiplying with 2 to convert the numbers in formula into a whole number:
So, the empirical formula is
.
Empirical mass = 
In order to determine the molecular formula:
n = 
n = 
So, the molecular formula is:

Answer:
The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.
The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.
Domain and range restrictions must be observed.
Explanation:
Calibration curves are tools necessary in understanding the instrumental response for any analyte.
A calibration curve is obtained by preparing a set of standard solutions with known concentrations of the analyte. The instrument response for each concentration is measured and plotted against the concentration of the standard solution. The linear portion of this plot may be used to determine the unknown concentration of a sample of the analyte.
The equation of the best-fit line is used to determine the concentration of the unknown sample.
Answer:
Kc = [C2H5OH]/{[C2H4][H2O]}
[H2O] = [C2H5OH]/{[C2H4] x Kc}
[H2O] = 1.69/(0.015 x 9.0 x 10^3) = 0.013 M
Explanation:
Kc is the equilibrium constant, it is egal to the product of the equilibrium concentration of the product dived by the product of the equilibrium concentration of the reactants.
with that formula and what is given, male the equilibrium concentration of H2O the subject of the formula and calculate its concentration by substituting given values.
Answers:
2. valence electrons
3. a bond formed when atoms share one or more pairs of electrons.
4. chemical formula
5. a. calcium - 2
b. carbon - 4
c. sulfur - 6
6. a. electrons
7. the elements that make up water can't be split into a simpler form, but water can. water is a liquid at room temperature, oxygen and hydrogen are gases at room temperature.
8. because it is made of oxygen and hydrogen and one is partially negative and one is partially positive.
explanation: you’re welcome.