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bija089 [108]
3 years ago
11

Given the equation representing a system at equilibrium:

Chemistry
2 answers:
marissa [1.9K]3 years ago
8 0

Answer:

Option (4) increasing the temperature

Explanation:

PCl5(g) + energy ⇌ PCl3(g) + Cl2(g)

The reaction above clearly indicates endothermic reaction since heat is required for the reaction to proceed to product.

As the heat is supplied, the temperature of reaction increases thereby making the reaction to proceed forward at a much faster rate and hence the equilibrium position will shift to the right. This is in accordance with Le Chatelier's principle will explained that for an endothermic reaction, an increase in temperature will cause the equilibrium position to shift to the right.

Yuliya22 [10]3 years ago
4 0

Answer:

increasing the temperature

Explanation:

Now look carefully at the reaction equation, notice the inclusion on an energy term on the left hand side;

PCl5(g) + energy ⇌ PCl3(g) + Cl2(g)

The inclusion of an energy term means that the reaction is endothermic. Energy is absorbed as the reaction goes from left to right.

Since energy is absorbed, increasing the temperature (supplying energy in the form of heat) will favour the forward reaction over the reverse reaction in accordance with Le Chatelier's principle. Hence the answer.

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Answer 10
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3 years ago
I NEED HELP ASAP! PLEASE BE GENUINE
love history [14]

1. The molar mass of the unknown gas obtained is 0.096 g/mol

2. The pressure of the oxygen gas in the tank is 1.524 atm

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>1. How to determine the molar mass of the gas </h3>
  • Rate of unknown gas (R₁) = 11.1 mins
  • Rate of H₂ (R₂) = 2.42 mins
  • Molar mass of H₂ (M₂) = 2.02 g/mol
  • Molar mass of unknown gas (M₁) =?

R₁/R₂ = √(M₂/M₁)

11.1 / 2.42 = √(2.02 / M₁)

Square both side

(11.1 / 2.42)² = 2.02 / M₁

Cross multiply

(11.1 / 2.42)² × M₁ = 2.02

Divide both side by (11.1 / 2.42)²

M₁ = 2.02 / (11.1 / 2.42)²

M₁ = 0.096 g/mol

<h3>2. How to determine the pressure of O₂</h3>

From the question given above, the following data were obtained:

  • Volume (V) = 438 L
  • Mass of O₂ = 0.885 kg = 885 g
  • Molar mass of O₂ = 32 g/mol
  • Mole of of O₂ (n) = 885 / 32 = 27.65625 moles
  • Temperature (T) = 21 °C = 21 + 273 = 294 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Pressure (P) =?

The pressure of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both side by V

P = nRT / V

P = (27.65625 × 0.0821 × 294) / 438

P = 1.524 atm

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

Learn more about ideal gas equation:

brainly.com/question/4147359

6 0
2 years ago
Convert 0.95 kilograms into centigrams. (1 g = 100 cg; 1 kg = 1000 g)
svet-max [94.6K]

Answer:

95,000 centigrams

Explanation:

There is 1000 CG in 0.01 kilograms

so you do 1000*95 which equals 95,000 centigrams.

6 0
3 years ago
Anyone know how to do this?
castortr0y [4]

Answer:

nah

Explanation:

just ignore this for now I don't know but it wants me to answer stuff

4 0
3 years ago
Two oxide of sulphur,A and B were analyzed and the results obtained showed that in oxide A,3.50g of sulphur combined with 6.00g
Nimfa-mama [501]

Answer:

See Explanaton

Explanation:

The law of multiple proportions states that when two same elements form more than a compound, the different masses of one element that combine with the same mass of the other element are in the ratio of small whole numbers.

<u>Oxide A</u>

3.50g of sulphur combined with 6.00g of oxygen

Oxygen:Sulphur = 6 : 3.5

<u>Oxide B</u>

2.80g of sulphur combined with 9.55g

Oxygen : Sulphur = 9.55 : 2.8

Therefore:

The ratio of Oxygen to Sulphur in Oxides A and B is:

\dfrac{\text{Oxygen}}{\text{Sulphur}} \implies  \dfrac{6}{3.5}:\dfrac{9.55}{2.8} = \dfrac{1.7}{1}:\dfrac{3.4}{1}=1:2

Ratio of Oxygen=1:2

There is exactly twice in Oxide B as in Oxide A.

This result illustrates the law of multiple proportions.

5 0
3 years ago
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