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kkurt [141]
3 years ago
6

Which sample contains a total of 6.0 x 1023 molecules? Select one: a. 4.0 g of He b. 14 g of Li c. 80 g of Br2 d. 4.0 g of H2

Chemistry
1 answer:
navik [9.2K]3 years ago
3 0

Answer:

Option a. 4 g of He

Explanation:

6.02×10²³ is the Avogadro's number. The amount of units that corresponds to 1 mol, in this case the units are molecules.

Let's find out which mass corresponds to 1 mol (mass / molar mass)

a. 4g / 4g/mol = 1 mol He

b. 14g / 6.94 g/mol = 2.01 mol Li

c. 80g /159.8 g/mol = 0.5 moles Br₂

d. 4g / 2g/mol = 2 mol H₂

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The answer is "Option B"

Explanation:

From the query, the following knowledge is derived:  

Yield in percentage = 47%  

Performance of theory = 4860 g  

Actual yield Rate =?  

The percentage return is defined simply by the ratio between both the real return as well as the conceptual return multiplied by the 100. It's also represented as numerically:

Rate = \frac{Existing \ Rate} {Theoretical \ Rate} \times 100

Now We can obtain the percent yield as followed using the above formula:  

\text{Yield in percentage}= \frac{Actual \ yield \ Rate} {Theorical \ Rate} \times  100

47\% = \frac{Actual \ yield \ Rate}{4860}

The value of the Actual yield Rate =47\% \times 4860

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<h3>What is an electrode?</h3>

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Therefore, neither of the two electrodes can be used with an inactive or inert material.

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brainly.com/question/13098144

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