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Lapatulllka [165]
3 years ago
11

A pharmaceutical company is making a large volume of nitrous oxide (NO). They predict they will be able to make a maximum amount

of 4860 grams with the materials they have in stock. From the previous 10 volumes they have made, they know that the percent yield of this reaction is fairly low at 47%. How much will the actual yield be? A. 228 grams B. 2284 grams C. 10340 grams D. 486 grams
Chemistry
1 answer:
iragen [17]3 years ago
3 0

Answer:

The answer is "Option B"

Explanation:

From the query, the following knowledge is derived:  

Yield in percentage = 47%  

Performance of theory = 4860 g  

Actual yield Rate =?  

The percentage return is defined simply by the ratio between both the real return as well as the conceptual return multiplied by the 100. It's also represented as numerically:

Rate = \frac{Existing \ Rate} {Theoretical \ Rate} \times 100

Now We can obtain the percent yield as followed using the above formula:  

\text{Yield in percentage}= \frac{Actual \ yield \ Rate} {Theorical \ Rate} \times  100

47\% = \frac{Actual \ yield \ Rate}{4860}

The value of the Actual yield Rate =47\% \times 4860

                                                        = \frac{47}{100} \times 4860 \\\\ = 2284.2 g

The Actual yield Rate= 2284.2 g.

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C8H8O2

Explanation:

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From the question given, we were told that molar mass of the compound is 136g/mol. This implies that:

[C4H4O]n = 136

Now, let us find the value of n in order to obtain the desired result. This is illustrated below:

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Respuesta:

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FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)

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