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andriy [413]
3 years ago
13

What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g

Chemistry
2 answers:
Anika [276]3 years ago
4 0
To get the percent yield, we will use this formula: ((Actual Yield)/(Theoretical Yield)) * 100% Values given: actual yield is 220.0 g theoretical yield is 275.6 g Now, let us substitute the values given. (220.0 grams)/(275.6 grams) = 0.7983 Then, to get the percentage, multiply the quotient by 100. 0.7983 (100) = 79.83% Among the choices, the most plausible answer is 79.8% <span>
</span>
Katen [24]3 years ago
4 0
<span>If the actual yield of ferrous sulfide is 220.0 g and its theoretical yield is 275.6 g, the percent yield of ferrous sulfide is 79.8%. Make a proportion. 220.0 g is x percent. 275.6 g is 100%. 220.0 g : x = 275.6 g : 100%. After crossing the products: x = 220.0 g * 100% : 275.6 g = 79.8%</span>
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This question is incomplete

Explanation:

This question is incomplete because of the absence of options. However, the compound C₆H₁₄ is hexane. Hexane is a member of saturated hydrocarbons (homologous series) called alkanes (with the general formula CₙH₂ₙ₊₂). The structure for an hexane is shown below

     H   H   H   H   H   H

      I     I    I     I     I     I

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which can also be written as

CH₃CH₂CH₂CH₂CH₂CH₃

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3 years ago
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The statement that best describes how an ionic compound dissolves in water is as follows: it separates into individual molecules and is an electrolyte, which is option C.

<h3>What is an ionic compound?</h3>

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Therefore, the statement that best describes how an ionic compound dissolves in water is as follows: it separates into individual molecules and is an electrolyte.

Learn more about ionic compound at: brainly.com/question/9167977

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