All categories

3 years ago

Which things are abiotic factors that are also basic needs for which living things compete?

Chemistry

1 answer:

geniusboy [140]3 years ago

4 0

Answer:

Sunlight. and maybe dead wood and sticks.

Explanation:

Lots of trees compete for the most sunlight. That's why if you go to a rain forest, there are different levels of ecosystems and sizes of trees.

Both beavers and otters compete for these sticks, if the beavers don't build strong enough, their home will collapse.

You might be interested in

What two states of matter are found during melting

kondaur [170]

Answer:

solid and liquid

Explanation:

6 0

4 years ago

Identify the variables in this hypothesis. If the pressure of a gas is increased, then the volume will decrease because the part

Kaylis [27]

Volume of matter decreases under pressure ... -under pressure, the particles in a gas are forced closer together ... factors affecting gas pressure ... -if pressure in a sealed container is lower than outside, gas will rush in ...

7 0

4 years ago

Read 2 more answers

3. Fill in: Name the organelle or organelles that perform each of the following functions.

Mekhanik [1.2K]

A. Chloroplasts

B. The cell wall and the vacuole

C. Vacuoles

D. The mitochondrion

8 0

3 years ago

Which of these is an example of a two-track mind?

Arturiano [62]

Answer:

The answer is D."We see whole images, while feature detectors detect specific"

6 0

4 years ago

What is the mass in grams of 1.00 x 10 24 atoms of Mn?

Alex17521 [72]

<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[Given] 1.00 × 10²⁴ atoms Mn

Step 2: Identify Conversions

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 91.2321 \ g \ Mn$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

91.2321 g Mn ≈ 91.2 g Mn

7 0

4 years ago

Read 2 more answers