Answer:
b
Step-by-step explanation:
divide both sides of the equation by 4 to leave s by itself
It’s 84 you just break into three pieces and find the side lengths
<em>Answer:</em>
<em>we have
</em>
<em>
256^{\frac{3}{4}}
</em>
<em>
we know that
</em>
<em>
256=2^{8}
</em>
<em>
substitute
</em>
<em>
256^{\frac{3}{4}}=(2^{8})^{\frac{3}{4}}=2^{\frac{24}{4}}=2^{6}=64
</em>
<em>
therefore
</em>
<em>
the answer is the option
</em>
<em>
64</em>
<em>this is what i found </em>
(i) Velocity is the rate of change of position, so if
<em>r</em><em>(t)</em> = <em>b</em> cos(<em>ω t </em>) <em>i</em> + <em>b</em> sin(<em>ω t </em>) <em>j</em> + <em>v</em> <em>t</em> <em>k</em>
then
<em>v</em><em>(t)</em> = d<em>r</em>/d<em>t</em>
<em>v</em><em>(t)</em> = -<em>b</em> <em>ω </em>sin(<em>ω t</em> ) <em>i</em> + <em>b</em> <em>ω</em> cos(<em>ω</em> <em>t</em> ) <em>j</em> + <em>v</em> <em>k</em>
The speed of the particle is the magnitude of the velocity, given by
|| <em>v</em><em>(t)</em> || = √[(-<em>b</em> <em>ω </em>sin(<em>ω t</em> ))² + (<em>b</em> <em>ω</em> cos(<em>ω</em> <em>t</em> ))² + <em>v</em> ²]
… = √[<em>b </em>²<em>ω </em>² + <em>v</em> ²]
(ii) The path is a helix. Suppose you zero out the <em>k</em> component. Then the path is a circle of radius <em>b</em>, and the value of <em>ω</em> determines how quickly a particle on the path traverses the circle. Now if you reintroduce the <em>k</em> component, the value of <em>v</em> will determine how far from the plane <em>z</em> = 0 the particle moves in a helical path as <em>t</em> varies.
(iii) Acceleration is the rate of change of velocity, so
<em>a</em><em>(t)</em> = d<em>v</em>/d<em>t</em>
<em>a</em><em>(t)</em> = -<em>b</em> <em>ω </em>²<em> </em>cos(<em>ω t</em> ) <em>i</em> - <em>b</em> <em>ω</em> ² sin(<em>ω</em> <em>t</em> ) <em>j</em>
Step-by-step explanation:
1/4 of the book = 66 pages
1/2 of the book = 132 pages
3/4 of the book = 132 + 66 = 198 pages
