Question

4

Answer 1

Answer: The space occupied by the gas at 400 torr and $25^{o}C$ is 250 mL.

Explanation:

Given: $V_{1}$ = 250 mL,    $P_{1}$ = 800 torr,     $T_{1} = 50^{o}C$

$V_{2} = ?$,         $P_{2}$ = 400 torr,        $T_{2} = 25^{o}C$

Formula used is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{800 torr \times 250 mL}{50^{o}C} = \frac{400 torr \times V_{2}}{25^{o}C}\\V_{2} = 250 mL$

Thus, we can conclude that space occupied by the gas at 400 torr and $25^{o}C$ is 250 mL.