A hammer of mass m falls from rest off of a roof and drops a height H onto your head.

1 answer:

6 0

For conservation of energy we have to:
mgH=mv²/2
Clearing
 v=sqrt(2gH)
Then, by definition
 F=Δp/Δt= Δ(mv)/ Δt=m Δ(v)/Δt=
 =m[sqrt(2gH)-0]/Δt= m[sqrt(2gH)]/ Δt
the answer is
F=m[sqrt(2gH)]/ Δt

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