Write the working mechanism of Mercury Barometer and explain its parts in short.
1 answer:
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Explanation:
It is given that,
Input voltage,
Input current,
Output current,
Number of turns in the secondary side of transformer,
We need to find the number of turns in the primary side of the transformer. The current to the number of turns in the input and output is given by :
Substituting all the above values
So,
So, the number of turns in primary side of the transformer is 5885.
(a)
The work done on the projectile is 9375 joule.
The work on the projectile is calculated as
W=F×d
=1250×7.5
=9375 joule
(b)
The speed of the projectile after 7.5 m is 27.38 m/s
First we need to find out the acceleration of the projectile
F=m×a
1250=25×a
a=50 m/
Now the velocity of the projectile after 7.5 m is calculated as
v^2=u^2+2a×s
v^2=0+2×50*7.5
v=27.38 m/s