To answer this question, we will use the equation of Clausius-Clapeyron which can be written as follows:
ln(P1/P2) = ΔH/R x (1/T2 - 1/T1)
Now, let's check the parameters in this equation:
P1 is the normal pressure of the vapor which is 4.24 kPa
T1 is the boiling point at this pressure which is 293 K
ΔH is the heat of vaporization given as 39.9 kJ/mol
T2 is given as 355.3 K
and we need to calculate P2
Substitute in the equation to get P2 as follows:
ln(4.24/P2) = 39.9/0.008314 x (1/355.3 - 1/293)
P2 = 101.2 kPa = 0.998766 atm
The correct answer is D) Malleability
hi im breanna
Answer:
The mole is simply a very large number that is used by chemists as a unit of measurement.
Explanation:
The mole is simply a very large number,
6.022
×
10
23
, that has a special property. If I have
6.022
×
10
23
hydrogen atoms, I have a mass of 1 gram of hydrogen atoms . If I have
6.022
×
10
23
H
2
molecules, I have a mass of 2 gram of hydrogen molecules. If I have
6.022
×
10
23
C
atoms, I have (approximately!) 12 grams.
The mole is thus the link between the micro world of atoms and molecules, and the macro world of grams and litres, the which we can easily measure by mass or volume. The masses for a mole of each element are given on the periodic table as the atomic weight. So, if have 12 g of
C
, I know, fairly precisely, how many atoms of carbon I have. Given this quantity, I know how many molecules of
O
2
are required to react with the
C
, which I could measure by mass or by volume.
Answer:
i am new but I haven't reached this level yet
