The ionic equation represents the element in cation and anionic form. The equation is given as OH⁻ + 2H⁺ → 2H₂O. Thus, option A is correct.
<h3>What is the ionic equation?</h3>
The ionic reaction equation is the representation of the chemicals dissociated as the ions in an aqueous solution. The ionic reaction is given as the cations and anions dissociated from the respective molecule or compound.
The ionic equation between potassium hydroxide and sulfuric acid is shown as,
2K⁺ + OH⁻ + 2H⁺ + SO₄²⁻ → 2H₂O + 2K⁺ + SO₄²⁻
It can also be written as,
Net ionic equation: OH⁻ + 2H⁺ → 2H₂O
Here, others are eliminated as they are spectator ions.
Therefore, option A. OH⁻ + 2H⁺ → 2H₂O is the net ionic equation.
Learn more about ionic equation here:
brainly.com/question/27980783
#SPJ1
In 250 mL of volumetric flask add 0.975875 grams of
and dissolve it in the 250 mL of water.
Given:
The solid of calcium fluoride.
To prepare:
The 250 mL solution of 0.100 M of fluoride ions from solid calcium fluoride.
Method:
Molarity of the fluoride ion solution needed = M = 0.100 M
The volume of the fluoride ion solution needed = V = 250 mL

The moles of fluoride ion needed = n
According to the definition of molarity:

Moles of fluoride ion = 0.025 mol
We know that solid calcium fluoride dissolves in water to give calcium ions and fluoride ions.

According to reaction, 2 moles of fluoride ions are obtained from 1 mole of calcium fluoride, then 0.025 moles of fluoride ions will be obtained from:

Moles of calcium fluoride = 0.0125 mol
Mass of calcium fluoride needed to prepare the solution :

Preparation:
- Weight 0.975875 grams of calcium fluoride
- Add weighed calcium fluoride to a volumetric flask of the labeled volume of 250 mL.
- Now add a small amount of water to dissolve the calcium fluoride completely.
- After this add more water up to the mark of the volumetric flask of volume 250 mL.
Learn more about molarity of solution ere:
brainly.com/question/10053901?referrer=searchResults
brainly.com/question/10270173?referrer=searchResults
Answer:
Estos elementos se denominan metales de transición, metales pesados, elementos del bloque D, etc.
Explanation:
Aquí, en esta pregunta, queremos saber la razón por la cual hay un espacio de 10 elementos entre el calcio, que es un elemento del grupo dos, y el galio, que es un elemento del grupo 3.
Al observar la tabla periódica, la tabla periódica moderna, notamos un bloque de elementos entre los elementos del grupo 2 y los elementos del grupo 3 en la tabla periódica.
Entonces, ¿por qué se colocan estos elementos entre ambos grupos? Se colocan aquí porque no pertenecen en su totalidad al grupo 2, ni tampoco al grupo 3.
Estos elementos presentan una especie de estados de oxidación variables que son responsables de una amplia variedad de propiedades comunes entre ellos.
40 g Ar.......6.023*10^23 atoms
x g Ar.......3.8*10^24 atoms
x=40*3.8*10^24/(6.023*10^23)=252,365g Ar