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marta [7]
3 years ago
14

The mass of an unidentified rock is 15.5 grams. Students determine the volume of the rock by placing the rock in a cylinder with

water. What was the density of the rock that the students should have calculated?
Hint: The graduated cylinder measures volume. Read the difference in water level.

Chemistry
1 answer:
Andre45 [30]3 years ago
3 0
The concept of water by displacement. D=m/v therefore m=15.5 g and volume=5 mL (final - initial) then calculate the density
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What is the net ionic equation for this reaction?
Elenna [48]

The ionic equation represents the element in cation and anionic form. The equation is given as OH⁻ + 2H⁺ → 2H₂O. Thus, option A is correct.

<h3>What is the ionic equation?</h3>

The ionic reaction equation is the representation of the chemicals dissociated as the ions in an aqueous solution. The ionic reaction is given as the cations and anions dissociated from the respective molecule or compound.

The ionic equation between potassium hydroxide and sulfuric acid is shown as,

2K⁺ + OH⁻ + 2H⁺ + SO₄²⁻ → 2H₂O + 2K⁺ + SO₄²⁻

It can also be written as,

Net ionic equation: OH⁻ + 2H⁺ → 2H₂O

Here, others are eliminated as they are spectator ions.

Therefore, option A. OH⁻ + 2H⁺ → 2H₂O is the net ionic equation.

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8 0
1 year ago
How would you prepare 250 mL of a 0.100 M solution of fluoride ions<br> from solid CaF2?
andrey2020 [161]

In 250 mL of volumetric flask add 0.975875 grams of CaF_2 and dissolve it in the 250 mL of water.

Given:

The solid of calcium fluoride.

To prepare:

The 250 mL solution of 0.100 M of fluoride ions from solid calcium fluoride.

Method:

Molarity of the fluoride ion solution needed = M = 0.100 M

The volume of the fluoride ion solution needed = V = 250 mL

1 mL = 0.001L\\V=250 mL=250\times 0.001 L=0.250 L

The moles of fluoride ion needed = n

According to the definition of molarity:

M=\frac{n}{V}\\0.100M=\frac{n}{0.250 L}\\n=0.100M\times 0.250 L=0.025 mol

Moles of fluoride ion = 0.025 mol

We know that solid calcium fluoride dissolves in water to give calcium ions and fluoride ions.

CaF_2(s)\rightarrow Ca^{2+}(aq)+2F^-(aq)

According to reaction, 2 moles of fluoride ions are obtained from 1 mole of calcium fluoride, then 0.025 moles of fluoride ions will be obtained from:

=\frac{1}{2}\times 0.025 mol=0.0125 \text{mol of } CaF_2

Moles of calcium fluoride = 0.0125 mol

Mass of calcium fluoride needed to prepare the solution :

=0.0125 mol\times 78.07 g/mol=0.975875 g

Preparation:

  • Weight 0.975875 grams of calcium fluoride
  • Add weighed calcium fluoride to a volumetric flask of the labeled volume of 250 mL.
  • Now add a small amount of water to dissolve the calcium fluoride completely.
  • After this add more water up to the mark of the volumetric flask of volume 250 mL.

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3 0
3 years ago
¿por qué entre el calcio (Ca) que pertenece al segundo grupo y el galio (Ga) que pertenece al tercer grupo hay 10 elementos, ¿Qu
34kurt

Answer:

Estos elementos se denominan metales de transición, metales pesados, elementos del bloque D, etc.

Explanation:

Aquí, en esta pregunta, queremos saber la razón por la cual hay un espacio de 10 elementos entre el calcio, que es un elemento del grupo dos, y el galio, que es un elemento del grupo 3.

Al observar la tabla periódica, la tabla periódica moderna, notamos un bloque de elementos entre los elementos del grupo 2 y los elementos del grupo 3 en la tabla periódica.

Entonces, ¿por qué se colocan estos elementos entre ambos grupos? Se colocan aquí porque no pertenecen en su totalidad al grupo 2, ni tampoco al grupo 3.

Estos elementos presentan una especie de estados de oxidación variables que son responsables de una amplia variedad de propiedades comunes entre ellos.

8 0
3 years ago
Read the statement about Mount Vesuvius. Mount Vesuvius erupted in 79 CE and destroyed the ancient city of Pompeii. Why is the s
Mamont248 [21]

Answer:

B

Explanation:

6 0
2 years ago
What is the mass of 3.8 × 1024 atoms of argon (Ar)?
gulaghasi [49]
40 g Ar.......6.023*10^23 atoms
x g Ar.......3.8*10^24 atoms
x=40*3.8*10^24/(6.023*10^23)=252,365g Ar
6 0
3 years ago
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