Question

How many moles of H2SO4 are required to completely neutralize 0.10 moles of Ca(OH)2?

Answer 1

Answer:

0.10 mol of sulfuric acid will neutralize 0.10 mol of calcium hydroxide.

Explanation:

$H_2SO_4+Ca(OH)_2\rightarrow CaSO_4+2H_2O$

1 mol of sulfuric acid reacts or neutralizes with 1 mol of calcium hydroxide.

Then 0.10 mole of calcium hydroxide will be neutralized by:

$\frac{1}{1}\times 0.10 mol= 0.10 mol$ of sulfuric acid

0.10 mol of sulfuric acid will neutralize 0.10 mol of calcium hydroxide.

Answer 2

Mole ratio:

H2SO4 + Ca(OH)2 = CaSO4 + 2 H2O

1 mole H2SO4 ----------- 1 mole Ca(OH)2
? moles H2SO4 --------- 0.10 moles Ca(OH)2

0.10 x 1 / 1

= 0.10 moles of H2SO4