How many moles of H2SO4 are required to completely neutralize 0.10 moles of Ca(OH)2?
2 answers:
Answer:
0.10 mol of sulfuric acid will neutralize 0.10 mol of calcium hydroxide.
Explanation:
1 mol of sulfuric acid reacts or neutralizes with 1 mol of calcium hydroxide.
Then 0.10 mole of calcium hydroxide will be neutralized by:
of sulfuric acid
0.10 mol of sulfuric acid will neutralize 0.10 mol of calcium hydroxide.
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Answer:
The net ionic equation for the given reaction :
Explanation:
...[1]
..[2]
...[3]
Replacing , NaI and
in [1] by usig [2] [3] and [4]
Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:
Molar mass of :
O2 = 16 * 2 = 32 g/mol
CO2 = 12 + 16 * 2 = 44 g/mol
<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
↓ ↓
2 moles 1 mole
2* 32 g O2 ----------> 1* 44 g CO2
x g O2 ------------> 10.0 g CO2
44 x = 2 * 32*10.0
44 x = 640
of O2
O2 = 16 * 2 = 32 g/mol
CO2 = 12 + 16 * 2 = 44 g/mol
<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
↓ ↓
2 moles 1 mole
2* 32 g O2 ----------> 1* 44 g CO2
x g O2 ------------> 10.0 g CO2
44 x = 2 * 32*10.0
44 x = 640