1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitrij [34]
3 years ago
6

Which statement does NOT explain the concept of the Doppler Effect? A. As an observer moves away from a stationary sound, the so

und waves are stretched making the pitch lower. B. As an observer approaches a stationary sound, the sound waves are compressed, making the pitch higher. C. As a sound source approaches a stationary object, the sound waves are compressed, making the pitch higher. D. As a sound source moves away from a stationary object, the sound waves are compressed, increasing the pitch.
Physics
1 answer:
Nookie1986 [14]3 years ago
4 0

Answer:

  D

Explanation:

When the sound is moving away from the stationary object the pitch decreases according to the Doppler Effect.

You might be interested in
Why doesn't electric current flow through rubber?
PolarNik [594]
Rubber is a insulator so current cannot pass through it where as metal is a conductor which allows current to pass through it
5 0
3 years ago
Read 2 more answers
Why was the microscope and its improvement an important part of the development of the cell theory?
netineya [11]

Answer:it’s is part of the cell theory because they where studying cells and to see it you need a microscope

Explanation:basically in the answer area

8 0
3 years ago
Read 2 more answers
Q1. In a 100m track event, the time taken by four runners is 10 sec., 10.2 sec., 10.4 sec and 10.6 sec. Find the ratio of their
Anna35 [415]
Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v=\frac{s}{t}
we get
V₁=\frac{100}{10}
V₁=10m/s

V₂=\frac{100}{10.2}
V₂=9.8m/s

V₃=\frac{100}{10.4}
V₃=9.61 m/s

V₄=\frac{100}{10.6}
V₄=9.43 m/s

V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43
8 0
3 years ago
A 1.5-kg mass attached to an ideal massless spring with a spring constant of 20.0 N/m oscillates on a horizontal, frictionless t
Molodets [167]

Answer:

Explanation:

a ) angular frequency ω = \sqrt{\frac{k}{m} }

k is spring constant and m is mass attached

ω = \sqrt{\frac{20}{1.5} }

= 3.6515 rad / s

frequency of oscillation n = 3.6515 / (2 x 3.14)

= .5814 s⁻¹

x = .1 mcos(ωt)

= .1 mcos(3.6515t)

b ) maximum speed = ωA , A is amplitude

= 3.6515 x .1

= .36515 m /s

36.515 cm /s

maximum acceleration = ω²A

= 3.6515² x .1

= 1.333 m / s²

c ) Kinetic energy at displacement x

= 1/2 m ω²( A²-x²)

potential energy =1/2 m ω²x²

so 1/2 m ω²( A²-x²) = 1/2 m ω²x²

A²-x² = x²

2x² = A²

x = A / √2

6 0
3 years ago
ANSWER IN LESS THAN A MIN!! EASY!​
Romashka [77]

Answer:

2 m/sec

Explanation:

3 0
3 years ago
Other questions:
  • Which molecule will form a solution with a very low pH?
    14·1 answer
  • With only a floor plan to reference, the designer would know what about a window.?
    9·1 answer
  • What is common to all fossil fuels?
    15·2 answers
  • How long does it take for the earth to rotate
    12·2 answers
  • A migrating bird flew across a lake at an average speed of 18 meters per second. Was the distance that the bird flew across the
    7·1 answer
  • The current supplied by a battery as a function of time is I(t) = (0.88 A) e^(-t*6 hr). What is the total number of electrons tr
    5·1 answer
  • Please write ONE complete sentence describing the relationship between Kinetic Energy and Gravitational Potential Energy in a sy
    13·1 answer
  • A river flows at a velocity of 3 km/h relative to the riverbank. A boat moves downstream at a velocity of 15 km/h relative to th
    12·1 answer
  • The phrase change in which a substance changes from a gas directly to a solid is
    12·1 answer
  • * A 5 kg ball is dropped from a height of 20 m. How much kinetic energy will it have 10 m above the ground? a. 490 J b. 392 J C.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!