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wolverine [178]
3 years ago
9

When you jump, you push down on the earth and it pushes back up against you. The earth pushing up against you is what causes you

to go into the air. Why doesn’t your push cause the earth to go down if your push on the earth is equal and opposite of the earth's push on you?
Physics
1 answer:
MissTica3 years ago
5 0

That's a great question !

The answer is:<em> It does !</em>

A push on an object causes the object to <u><em>accelerate</em></u> in the direction of the force.  

The <em>less</em> mass the object has, the <em>more</em> the force accelerates it.

Now, when you jump, the forces on you and on the Earth are equal forces.

The up force on you causes you to accelerate up by some amount.

The down force on the Earth causes the Earth to accelerate down by some amount.

The Earth's mass is something like 5,972,000,000,000,000,000,000,000 kg, while your mass is something like 50 kg.

The Earth has something like 119,400,000,000,000,000,000,000 <em>times</em> as much mass as you have.

So your acceleration is something like 119,400,000,000,000,000,000,000 <em>times as great as the Earth's acceleration.</em>

==> The Earth's downward acceleration, caused by your jump, is there.  It's just too small to notice.

<em>BUT . . .</em> That's the reason why seismometers (instruments to detect and measure the vibrations from distant earthquakes) have to be located as far as possible from cities and busy roads.

In places that are too close to cities and roads, the Earth's surface is always vibrating, wiggling, jiggling, heaving and weaving, in reaction to the forces of people walking around, cars and trucks driving around, even rain falling down.  And kids jumping up and down !  

In such places, these people-motions are louder and stronger than the vibrations coming from distant earthquakes.  Seismometers wouldn't work there.    

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The volume of the gas at 500^{\circ} \text{C} is \fbox{\begin\ 5.576\,{\text{L}}\\\end{minispace}}.

Further Explanation:

Consider the pressure of the gas to be constant.  

The change in the volume of the gas when the temperature of the gas is varied by keeping the pressure of the gas at a constant value is defined by the Charles' Law.

Concept:

According to the Charles law, the volume of the gas is directly proportional to the temperature of the gas at constant pressure.

The Charles' law can be stated as:

\fbox{\begin\\V\propto T\\\end{minispace}}

The above expression can we written as.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Convert the temperature of the gas into kelvin.

T=273+T^\circ\text{C}}}

Here, T is the temperature in kelvin and T^\circ\text{C}}} is the temperature in centigrade.  

The initial temperature of the gas is 50^\circ\text{C}. The temperature of the gas in kelvin is.  

\begin{aligned}{T_1}&=273+50\\&=323\,{\text{K}}\\\end{aligned}

The final temperature of the gas is 500^\circ\text{C} . The temperature in kelvin is.  

\begin{aligned}{T_2}&=273+500\\&=773\,{\text{K}}\\\end{aligned}

Substitute the values of temperature and volume in the expression of the Charles' Law.  

\begin{aligned}{V_2}&=\frac{{{T_2}}}{{{T_1}}}{V_1}\\&=\frac{{773\,{\text{K}}}}{{323\,{\text{K}}}}\left({2.33\,{\text{L}}}\right)\\&=5.576\,{\text{L}}\\\end{aligned}

Thus, the volume of the gas at 500^\circ\text{C}} will be \fbox{\begin\ 5.576\,{\text{L}}\\\end{minispace}}.

Learn More:  

1. Examples of wind and solar energy brainly.com/question/1062501

2. Stress developed in a wire brainly.com/question/12985068

Answer Details:  

Grade: High school  

Subject: Physics  

Chapter: Gas law  

Keywords:  

Charles law, temperature, volume, initial, final, kelvin, centigrade, 50 C, 500 degree, 500 C, 50 degree, 2,33 L, gas expand, sample, heated.

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