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GREYUIT [131]
3 years ago
5

A girl at an airport rolls a ball north on a moving walking that moves east. If the ball’s speed with respect to the walkway is

0.15m/s and the walkway moves at a speed of 1.50m/s, what is the velocity of the ball relative to the ground?
Physics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

We have to add two vectors.

Vector #1: 0.15 m/s north

Vector #2: 1.50 m/s east

Their sum:

Magnitude: √(0.15² + 1.50²)

Magnitude = √(0.0225+2.25)

Magnitude = √2.2725

Magnitude = <em>1.5075 m/s</em>

Direction = arctan(0.15/1.50) north of east

Direction = <em>5.71° north of east</em>

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In a heat engine, if 500 J of heat enters the system, and the piston does 300 J of work.
Alex Ar [27]

Answer: The final answer is 1,700 J

Explanation: According to first law of thermodynamics:

=Final energy-initial energy=Change in internal energy

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w = work done by or on the system

w = work done by the system=  {Work done by the system is negative as the final volume is greater than initial volume}

q = +500J   {Heat absorbed by the system is positive}

w = work done by the system = -300J

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7 0
3 years ago
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A car's velocity changes from 40 m/s to 30 m/s in 40 seconds. What is the
valina [46]

Answer:

- 0.25m/s²

Explanation:

Given parameters:

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Final velocity  = 30m/s

Time taken  = 40s

Unknown:

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Solution:

Acceleration is the rate of change of velocity with time.

 So;

  Acceleration  = \frac{Final velocity - Initial velocity }{time }  

 Acceleration  = \frac{30  - 40}{40}    =  - 0.25m/s²

This implies that the car will decelerate at a rate of 0.25m/s²

7 0
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Answer: 0

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musickatia [10]

Answer:

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Hope this helps a bit,

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