Answer:
The rate of change of the distance between the helicopter and yourself (in ft/s) after 5 s is 
ft/ sec
Explanation:
Given:
h(t) = 25 ft/sec
x(t) = 10 ft/ sec
h(5) = 25 ft/sec . 5 = 125 ft
x(5) = 10 ft/sec . 5 = 50 ft
Now we can calculate the distance between the person and the helicopter by using the Pythagorean theorem
Lets find the derivative of distance with respect to time
Substituting the values of h(t) and x(t) and simplifying we get,
= 
= ft / sec
Answer:
d. Boyle's
Explanation:
Boyle's Law: States that the volume of a fixed mass of gas is inversely proportional proportional to its pressure, provided temperature remains constant.
Stating this mathematically. this implies that:
V∝1/P
V = k/P, Where k is the constant of proportionality
PV = k
P₁V₁ = P₂V₂
Where P₁ and P₂ are the initial and final pressure respectively, V₁ and V₂ are the the initial and final volume respectively.
Hence the right option is d. Boyle's
Http://www.calculator.net/pace-calculator.html?ctype=distance&ctime=05%3A00%3A00&cdistance=5&cdistanceunit=Miles&cpace=02%3A00%3A00&cpaceunit=tpm&printit=0&x=87&y=24 a pace calculator
First of all, we need to convert the angular speed from rev/min into rev/s:
The angular acceleration is the variation of angular speed divided by the time:
And this is constant, so we can use the following equation to calculate the angle through which the engine has rotated:
so, 5 revolutions.
