22/7 lord to the nearest hundreds.
Step-by-step explanation:
yes the volume and use 3.14 for PI is 22/7 lord to the nearest hundreds.
Answer:
-6.67 im pretty sure
Step-by-step explanation:
4+5=9
9-6=3
3/7=0.43
0.43-7=-6.67
the calculator says sum else but like who cares right? lol
The second option - 3/25.
The probability of the first one is 3 blue socks over 10 socks in total = 3/10
The probability of the second one is 4 red socks over 10 socks in total = 4/10
Multiply the two probabilities to get the probability of having the first sock as blue and the second sock as red.
3/10 * 4/10 = 3/25
Answer:
Step-by-step explanation:
Combine like terms
7x^6
2x^5+5x^5= 7x^5
8x^3
-3x^2-6x^2= -9x^2
9x+2x= 11x
-5
Put back into order
7x^6+7x^5+8x^3-9x^2+11x-5
Check the picture below. We know that the rectangle has a length of AB and a width of AD, so simply let's find those distances to get the perimeter and area, recall that the perimeter is simply two lengths plus two widths, and the area is just length times width.
![~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AB=\sqrt{[4 - 2]^2 + [5 - 3]^2}\implies AB=\sqrt{2^2+2^2}\implies \boxed{AB=2\sqrt{2}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20A%28%5Cstackrel%7Bx_1%7D%7B2%7D~%2C~%5Cstackrel%7By_1%7D%7B3%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B5%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20AB%3D%5Csqrt%7B%5B4%20-%202%5D%5E2%20%2B%20%5B5%20-%203%5D%5E2%7D%5Cimplies%20AB%3D%5Csqrt%7B2%5E2%2B2%5E2%7D%5Cimplies%20%5Cboxed%7BAB%3D2%5Csqrt%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad D(\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill AD=\sqrt{[3 - 2]^2 + [2 - 3]^2} \\\\\\ AD = \sqrt{1^2+(-1)^2}\implies \boxed{AD=\sqrt{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\large Perimeter}}{2\sqrt{2}+2\sqrt{2}+\sqrt{2}+\sqrt{2}}\implies 6\sqrt{2} \\\\\\ \stackrel{\textit{\large Area}}{2\sqrt{2}\cdot \sqrt{2}\implies 2\sqrt{2^2}}\implies 4](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20A%28%5Cstackrel%7Bx_1%7D%7B2%7D~%2C~%5Cstackrel%7By_1%7D%7B3%7D%29%5Cqquad%20D%28%5Cstackrel%7Bx_2%7D%7B3%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%20~%5Chfill%20AD%3D%5Csqrt%7B%5B3%20-%202%5D%5E2%20%2B%20%5B2%20-%203%5D%5E2%7D%20%5C%5C%5C%5C%5C%5C%20AD%20%3D%20%5Csqrt%7B1%5E2%2B%28-1%29%5E2%7D%5Cimplies%20%5Cboxed%7BAD%3D%5Csqrt%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20Perimeter%7D%7D%7B2%5Csqrt%7B2%7D%2B2%5Csqrt%7B2%7D%2B%5Csqrt%7B2%7D%2B%5Csqrt%7B2%7D%7D%5Cimplies%206%5Csqrt%7B2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20Area%7D%7D%7B2%5Csqrt%7B2%7D%5Ccdot%20%5Csqrt%7B2%7D%5Cimplies%202%5Csqrt%7B2%5E2%7D%7D%5Cimplies%204)
