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patriot [66]
3 years ago
14

Swimming pool A is 50 feet by 34 feet. Swimming pool B is 6 times as long as swimming pool A. How big is both swimming pools?​

Mathematics
2 answers:
Sliva [168]3 years ago
5 0
Pool a is 1700 ft
Pool B is 10200ft
Alex17521 [72]3 years ago
5 0
Swimming pool A is 1700 feet
Swimming pool B is 10200 feet
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Step-by-step explanation:

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Answer

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8 0
3 years ago
Write the following number in standard decimal form.<br> seven and sixty-one thousandths
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A researcher records the hospital admission rates for coronary heart disease at 10 local hospitals. She finds that 2 different h
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The central tendency researcher use to describe these data is "mode".

<h3>What is mode?</h3>

The value that appears most frequently in a data set is called the mode. One mode, several modes, or none at all may be present in a set of data. The mean, or average of a set, and the median, or middle value in a set, are two more common measurements of central tendency.

Calculation of mode is done by-

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To know more about the mode of the data, here

brainly.com/question/27951780

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6 0
2 years ago
How to solve logarithmic equations as such
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\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
On a coordinate grid, Ming's house is located 2 blocks to the right and blocks up from (0. 0). Joe's house is located 3 blocks t
kolbaska11 [484]
If o<span>n a coordinate grid, Ming's house is located 2 blocks to the right and (I suppose also 2) blocks up from (0. 0), then the ordered pair that describes the location of Ming's house is (2,2) (moving right 2 units from some point you have to add 2 units to the x-coordinate of the point from which you are moving and moving up 2 units from this point you have to add 2 units to y-coordinate of the point from which you are moving up).
</span>
If Joe's house is located 3 blocks to the right and 2 blocks down from Ming's house, then the ordered pair that describes the location of Ming's house is (2+3,2-2), that is (5,0) <span><span>(moving right 3 units from some point you have to add 3 units to the x-coordinate of the point from which you are moving and moving down 2 units from the point you have to substract 2 units from y-coordinate of the point from which you are moving down)</span>.</span>


3 0
3 years ago
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