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Ede4ka [16]
3 years ago
9

What tool do I need to use to find the molar mass?

Chemistry
1 answer:
Inga [223]3 years ago
5 0

Answer:

I never thought of it as a tool, but I think you refer to Atomic Weight. The total atomic weight of the atoms in a molecule is its Mass in Moles.

Take a really simple example H2O. The atomic weight of Oxygen is 16, Hydrogen is 1, and so added, 1 + 1 + 16 = 18; the mass of 1 mole of water is 18g. Same for Benzene, C6H6; atomic weight of carbon is 12, so 6 x 12 = 72, add 6 x 1, or 6, and 72 + 6 = 78

Explanation: The sum of the atomic weights of the atoms in a molecule will give you the Molecular Weight, I.e. the Mass of 1 Mole of thst molecule.

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Check the approach to obtain the correct conversion equation. Use the temperature in °F to find the temperature in °C.
Maru [420]

Answer:

( °F − 32) × 5/9 =  °C

Explanation:

Also there is a mental calculation to convert from Fahrenheit to Celsius. The ratio 5/9 is approximately equal 0.55555….

Subtract 32º to adapt the equivalent in the Fahrenheit scale.

Divide the degrees Celsius by 2 (multiply by 0.5).

Take 1/10 of this number (0.5 * 1/10 = 0.05) and add it to the number obtained previously.

Example: Convert 98.6º F to Centigrade.

98.6 - 32 = 66.6

66.6 * 1/2 = 33.3

33.3 * 1/10 = 3.3

33.3 + 3.3 = 36.6 which is an approximation in degrees Centigrade

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4.8 L sample of helium gas contains 0.22 moles of helium - How many additional moles of herum gas must be added to the sample to
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7 0
2 years ago
An antacid tablet with an active ingredient of CaCO3 was dissolved in 50.0 mL of 0.300 M HCl. When this solution was titrated wi
yaroslaw [1]

Answer:

Explanation:

mole of HCl remaining after reaction with CaCO₃

= .3 M of NaOH of 32.47 mL

= .3 x .03247 moles

= .009741 moles

Initial HCl taken = .3 x .005 moles = .0015 moles

Moles of HCl reacted with CaCO₃

= .009741 - .0015 = .008241 moles

CaCO₃     +    2HCl   =   CaCl₂  +  CO₂  +  H₂O .

1 mole        2 moles

2 moles of HCl reacts with 1 mole of  CaCO₃

.008241 moles of HCl reacts with .5 x .008241 moles of  CaCO₃

CaCO₃ reacted with HCl =  .5 x .008241 = .00412 moles

the mass (in grams) of calcium carbonate in the tablet

= .00412 x 100 = .412 grams . ( molar mass of calcium carbonate = 100 )

5 0
2 years ago
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