Answer:
2 moles of solute.
Explanation:
Molarity is defined as number of moles of solute present in one litre of solution.
Hence one molar solution of NaCl means 1 mole of NaCl is present in 1 litre of solution.
Molarity = 
For 1 litre of solution 1 mole of solute is required to make a one molar solution.
Hence for 2 litres of solution we require 2 moles of solute to keep it one molar.
Answer:
13.5
Explanation:
Molar mass of Fe2O3 = 2*56 + 16*3 = 112 + 48 =160 approximate value
Number of moles of Fe2O3 = mass/molar mass = 40/160 = 0.25 mol
The reaction is balanced. Fine
1 mol of Fe2O3--------> 2 mol of Al
0.25 mol--------> 0.25*2 = 0.5 mol of Al
Mass of Al required = Number of moles * Molar mass
= 0.5 * 27 = 13.5 g
We need to know the value of van't hoff factor.
The van't hoff factor is: 2.66 or 2.7 (approximately)
(NH₄)₂SO₄ is an ionic compound, so it dissociates in solution and produces 3 ionic species. Therefore van't hoff factor is more than one.
From the equation: Δ
=i 
.m, where Δ= elevation of boiling point=102.5 - 100=2.5°C.
m=molality of solute=1.83 m (Given)
= Ebullioscopic constant or Boiling point elevation constant= 0.512°C/m (Given)
i= Van't Hoff factor
So, 2.5= i X 0.512 X 1.83
i=
i=2.66= 2.7 (approx.)
Oxygen can be obtained from water using electrolysis process as follows:
2 H2O .............> 2H2 + O2
It is given that:
molar mass of water = 10.01 grams and molar mass of O2 = 32 grams
From the balanced chemical equation, we can conclude that:
2 moles of water produce 1 mole of oxygen
2 x 18.01 = 36.02 grams of water produce 32 grams of oxygen.
To calculate how many grams of water must react to produce 50 grams of oxygen, we can use cross multiplication as follows:
mass of required water = 56.28125 grams
Answer:
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