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Fudgin [204]
3 years ago
7

What is the percentage by mass of solution formed by dissolving 36.0 grams of HCl in 98.0 grams of water?

Chemistry
2 answers:
Montano1993 [528]3 years ago
5 0

Answer:

The percentage by mass of the solution is 26.86%.

Explanation:

Mass of hydrochloric acid = 36.0 g

Mass of water = 98.0 g

Solution = HCl+ Water

Mass of the solution =  36.0g + 98.0 g = 134 g

mAss percentage of the solution:

\frac{\text{Mass of solute}}{\text{Mass of the solution}}\times 100

\frac{36 g}{134 g}\times 100=26.86\%

The percentage by mass of the solution is 26.86%.

Svetradugi [14.3K]3 years ago
4 0
Convert HCl and H2O to mols.

36.0g HCl = 0.987mols HCl

98.0g H2O = 5.44mols H2O

According to the stoichiometric ratio of HCl,
you have 0.987mols of H and 0.987mols of Cl.

According to the stoichiometric ratio of H20, you have 10.88mols of H and 5.44mols of O.

Summing them:
11.867 mols H
0.987 mols Cl
5.44 mols O

Convert each back to grams and divide by total mass and multiply by 100 to determine percentage by mass.

11.867mol H = 11.96g H
0.987mols Cl = 34.99g Cl
5.44mols O = 87.03g O

11.96/(36.0+98.0)(100) = 8.93% H
34.99/(36.0+98.0)(100) = 26.11% Cl
87.03/(36.0+98.0)(100) = 64.96% O
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The most abundant source of energy from a reservoir is hydroelectric power plant.

Therefore, the energy source from a reservoir would provide affordable, abundant electricity for a factory is a hydroelectric power plant.

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7 0
1 year ago
Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO;?
faltersainse [42]

Answer:

K₂CO₃    

Explanation:

Given parameters:

Number of moles of K = 0.104mol

Number of moles of C = 0.052mol

Number of moles of O = 0.156mol

Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

  • Divide the given moles through by the smallest which is C, 0.052mol.
  • Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
  • This is the empirical formula

Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

3 0
3 years ago
What is the significance of equivalence point in acid base titrations?
iren2701 [21]

Hey there!

The equivalence is point in a titration is the point at which you have neutralized all of your base/acid with your titrant acid/base from a buret. This can be seen with indicators which change color at the equivalence point in a titration to signal to you that all of your base/acid has been reacted with. For example, all your molecules of OH⁻ from a NaOH base in a beaker have been neutralized by H⁺of HCl acid from your titrant in a buret leaving only Na⁺ ions and Cl⁻ ions and neutral H₂O molecules.

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An observation balloon was filled with 0.50 atmospheres of Helium, 54.0 mm Hg of Nitrogen, and 0.400 atmospheres of Hydrogen. Wh
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