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mestny [16]
3 years ago
14

Three vertices of a square are (-2, 2), (-2, -3), and (3, -3). What is the fourth vertex of the square?

Mathematics
1 answer:
Oxana [17]3 years ago
5 0
(-2,2) and (-2,-3) are the bottom vertices, since (3,-3) is the top you can tell that it is the upper left vertex since it lines up with (2,-3), so the fourth vortex would line up with (-2,2) and would therefore be C. (3,2)
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On selling an article for Rs 2300, a shopkeeper made a profit of 15 %. find the cost price of the article.
Ede4ka [16]

Let the cost price of article be x :

x + x × ( 15/100 ) = 2300

x + x × ( 5 × 3 / 5 × 20 ) = 2300

x + x × ( 3 / 20 ) = 2300

x + ( 3 × x / 20 ) = 2300

x + ( 3x / 20 ) = 2300

( 20x / 20 ) + ( 3x / 20 ) = 2300

20x + 3x / 20 = 2300

23x / 20 = 2300

Multiply both sides by 20

( 23x / 20 ) × 20 = 2300 × 20

23x = 2300 × 20

23x = 23 × 2000

Divide both sides 23

23x ÷ 23 = ( 23 × 2000 ) ÷ 23

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4 0
3 years ago
The height of a triangle is 4 inches. Greater than twice it's base. The area of the triangle is no more than 168 in.². Which any
mestny [16]

Step-by-step explanation:

this problem seeks to test our knowledge on word problems and algebra

<u>Solution</u>

let the base be x, and

the height h = 2x+4

We know that area of a triangle is given as

A= \frac{1}{2} b*h

substituting our given values we have

168= \frac{1}{2} x*(2x+4)\\\\168= \frac{2x^2+4x}{2} \\\\168= x^2+2x\\\\

re-arranging we have

x^2+2x-168=0\\\\

we can now find two factors that will add up to give 2 and multiply to give -168

they are 14 and -12

x^2-14x+12x-168=0\\\\x(x-14)+12(x- 14)=0\\\\x+12=0\\\\x=-12\\\\x-14=0\\\\x=14

The possible base of the triangle is 14 in

and the height is

h= 2x+4\\\\h=2(14)+4\\\\h= 28+4\\\\\h= 32 in

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3 years ago
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Vlad1618 [11]

Answer:

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3 years ago
HJ and KM are parallel lines.
Reil [10]

it's JIL and HIL.

hope it helps :)

8 0
3 years ago
What number is 0.1 less than 11.6?
adell [148]
11.5
because you will subtract 0.1 from 11.6.
4 0
3 years ago
Read 2 more answers
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