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Oliga [24]
3 years ago
9

How many milliliters of a 3.0 M HCl solution are required to make 250.0 milliliters of 1.2 M HCl?

Chemistry
1 answer:
mixer [17]3 years ago
8 0
 formulae for finding is
(Mi)(Vi) = (Mf)(Vf) 
<span>(3.0M)(x) = (500.mL/1000)(1.0M)
</span>convert 500ml to liter

<span>x = (0.5 moles)/(3.0 moles/liter) </span>
<span>x = 0.17 Liters = 1.7 x 10^2 mL HCl</span>
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The molarity (M) of an aqueous solution containing 22.5 g of sucrose (C12H22O11) in 35.5 mL of solution is ________.
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Answer:

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Explanation:

From the question given above, the following data were obtained:

Mass of sucrose (C12H22O11) = 22.5 g

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Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:

Mass of sucrose (C12H22O11) = 22.5 g

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Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

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35.5 mL = 35.5 mL × 1 L / 1000 mL

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