Work is done when a force is in the same direction as the object moves.
Explanation:
The work done by a force in moving an object is given by the equation

where
F is the magnitude of the force
d is the displacement of the object
is the angle between the directions of F and d
From the equation, we notice the following:
- Work is done by a force when the force is in the same direction as the object moves. In fact, in this case,
, and so
, which means that the work done simply becomes 
- When the force is perpendicular to the motion of the object,
and
, which means that no work done - Technically, work is also done when the force is not parallel to the motion of the object: in this case, the factor
means that only the component of the force parallel to the direction of motion contributes to do work on the object.
Therefore, the correct answer is
Work is done when a force is in the same direction as the object moves.
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The ball will take 0.45 seconds to reach the ground
<h3>How will we solve this question?</h3>
We will use Newton’s laws of motion, so
H=
taking height= 1m


<h3>What are the three laws of motion given by Newton?</h3>
The 3 laws of motion given by Newton are as follows:
1) Unless an unbalanced force acts upon it, an item at rest remains at rest, and an object in motion continues to move in a straight line at a constant pace.
2) An object's acceleration is influenced by its mass and the force being applied.
3) Whenever one thing applies force to another, the second object applies the opposing, equal force to the first.
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Answer
given,
F₁ is horizontal = 40 N
F₂ is normal = 20 N
F₃ is parallel = 30 N
work done by
W₂ = 0 as force is acting perpendicular to the direction of motion.
as the motion moved to 0.8 cm
W₃ = F₃ x d
W₃ = 30 x 0.8
W₃ = 24 J
W₁ = F₁ x d
W₁ = F₁ cos ∅ x d
W₁ = 40 cos 30⁰ x 0.8
W₁ = 27.21 J
The final vertical velocity of the object is 705.6 m
Explanation:
Here we have to analyze the vertical motion of the object, which is a free fall motion, with constant acceleration of

towards the ground due to gravity.
Therefore, we can use the following suvat equation:

where
v is the final vertical velocity
u is the initial vertical velocity
is the acceleration
t is the time
Since the object is dropped,
u = 0
Therefore, the magnitude of the vertical velocity of the object after t = 72 seconds is:

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