Now, there is some information missing to this problem, since generally you will be given a figure to analyze like the one on the attached picture. The whole problem should look something like this:
"Beam AB has a negligible mass and thickness, and supports the 200kg uniform block. It is pinned at A and rests on the top of a post, having a mass of 20 kg and negligible thickness. Determine the two coefficients of static friction at B and at C so that when the magnitude of the applied force is increased to 360 N , the post slips at both B and C simultaneously."
Answer:
Explanation:
In order to solve this problem we will need to draw a free body diagram of each of the components of the system (see attached pictures) and analyze each of them. Let's take the free body diagram of the beam, so when analyzing it we get:
Sum of torques:
When solving for N we get:
Now we can analyze the column. In this case we need to take into account that there will be no P-ycomponent affecting the beam since it's a slider and we'll assume there is no friction between the slider and the column. So when analyzing the column we get the following:
First, the forces in y.
Next, the forces in x.
We can find the x-component of force P like this:
and finally the torques about C.
With the static friction force in point B we can find the coefficient of static friction in B:
And now we can find the friction force in C.
and now we can use this to find static friction coefficient in point C.
Answer:
Option C. Rate of change of velocity
Explanation:
To know the correct answer to the question, it is important we know the definition of power.
Power can be defined as the rate at which work is done. Mathematically, it is expressed as:
Power = work / time
Work and energy has the same unit of measurement i.e joule. Thus, power can also be defined as the rate at which energy is transferred i.e
Power = enery / time
Energy is measured in Joules and time in second. Thus, power can also be defined as amount of joules transfered per second.
Power = Joule / sec
The rate of change of velocity on the other hand is termed acceleration.
Thus, the answer to the question is option C.
Answer:
The gravitational potential energy of the man
= mass of the man(m) × gravitational acceleration(g) × height (h)
80 Kg × 9.8 m/s^2 × 60 m
80 × 9.8 x 60 ( kg ×m^2/s^2)
47040 Joules (ans)
Hope it helps
Explanation:
A chemical reaction is a reaction in which two or more species combine together to form a molecule with a new chemical composition.
In a chemical reaction, the reactants are written on left hand side pointing a forward arrow towards the products which are written on the right hand side.
For example, chemical reaction between hydrogen and oxygen will result in the formation of water. The reaction equation will be as follows.
The first thing we have to do for this case is write the kinematic equationsto
vf = a * t + vo
rf = a * (t ^ 2/2) + vo * t + ro
Then, for the bolt we have:
100% of your fall:
97 = g * (t ^ 2/2)
clearing t
t = root (2 * ((97) / (9.8)))
t = 4.449260429
89% of your fall:
0.89*97 = g * (t ^ 2/2)
clearing t
t = root (2 * ((0.89 * 97) / (9.8)))
t = 4.197423894
11% of your fall
t = 4.449260429-4.197423894
t = 0.252
To know the speed when the last 11% of your fall begins, you must first know how long it took you to get there:
86.33 = g * (t ^ 2/2)
Determining t:
t = root (2 * ((86.33) / (9.8))) = <span>
4.19742389 </span>s
Then, your speed will be:
vf = (9.8) * (4.19742389) = 41.135 m / s
Speed just before reaching the ground:
The time will be:
t = 0.252 + <span>
4.197423894</span> = <span>
4.449423894</span> s
The speed is
vf = (9.8) * (4.449423894) =<span>
<span>43.603</span></span> m / s
answer
(a) t = 0.252 s
(b) 41,135 m / s
(c) 43.603 m / s
