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3 years ago

If you are going to see which food dye diffuses fastest in water. Which variables do you measure How will you do this?

1 answer:

6 0

You should be searching for your independent variable, and think about every variable to keep the same. The only thing that should be changing between separate experiments would be the type of food dye, you keep the amount of dye used, the place you're distributing to, the location, temp... the list goes on. Your dependent variable is the outcome: Which food dye diffuses first.

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All objects emit ______ radiation?<br> A-electromagnetic<br> B-kinetic<br> D-solar

natulia [17]

A, electromagnetic radiation

6 0

3 years ago

System A has masses m and m separated by a distance r; system B has masses m and 2m separated by a distance 2r; system C has mas

Anna [14]

Answer:

System D --> System C --> System A --> System B

Explanation:

The gravitational force between two masses m1, m2 separated by a distance r is given by:

$F=G \frac{m_1 m_2}{r^2}$

where G is the gravitational constant. Let's apply this formula to each case now to calculate the relative force for each system:

System A has masses m and m separated by a distance r:

$F=G\frac{m \cdot m}{r^2}=G \frac{m^2}{r^2}$

system B has masses m and 2m separated by a distance 2r:

$F=G\frac{m \cdot 2m}{(2r)^2}=G \frac{2m^2}{4r^2}=\frac{1}{2} G \frac{m^2}{r^2}$

system C has masses 2m and 3m separated by a distance 2r:

$F=G\frac{2m \cdot 3m}{(2r)^2}=G \frac{6m^2}{4r^2}=\frac{3}{2} G \frac{m^2}{r^2}$

system D has masses 4m and 5m separated by a distance 3r:

$F=G\frac{4m \cdot 5m}{(3r)^2}=G \frac{20m^2}{9r^2}=\frac{20}{9} G \frac{m^2}{r^2}$

Now, by looking at the 4 different forces, we can rank them from the greatest to the smallest force, and we find:

System D --> System C --> System A --> System B

5 0

3 years ago

ILL MARK BRAINIEST IF YOU DO THIS CORRECTLY!!!

IRINA_888 [86]

Explanation:

1)5.8m/s

2)5.15m/s^2

3)12.69m/s

8 0

2 years ago

A ball is thrown horizontally from the top of a building 22.3 m high. The ball strikes the ground at a point 127 m from the base

DochEvi [55]

Answer:

t = 2.13 s

Explanation:

given,

height of the building = 22.3 m

horizontal distance = 127 m

acceleration due to gravity = 9.8 m/s²

time for which ball is in motion = ?

using equation of motion

$s = u t + \dfrac{1}{2}gt^2$

initial velocity is zero

$s = \dfrac{1}{2}gt^2$

$t = \sqrt{\dfrac{2s}{g}}$

$t = \sqrt{\dfrac{2\times 22.3}{9.8}}$

t = √4.551

t = 2.13 s

8 0

3 years ago

Consider a 7 m stretched string that is clamped at both ends. What is the longest wavelength standing wave that it can support (

user100 [1]

A vibrating stretched string has nodes or fixed points at each end. The string will vibrate in its fundamental frequency with just one anti node in the middle - this gives half a wave.

$l=\frac{\lambda }{2}$

Rearranging for the wavelength

$\lambda=2l$

$\lambda =2(7)$

$\lambda = 14m$

Therefore the longest wavelength standing wave that it can support is 14m

7 0

3 years ago