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3 years ago

If you are going to see which food dye diffuses fastest in water. Which variables do you measure How will you do this?

1 answer:

6 0

You should be searching for your independent variable, and think about every variable to keep the same. The only thing that should be changing between separate experiments would be the type of food dye, you keep the amount of dye used, the place you're distributing to, the location, temp... the list goes on. Your dependent variable is the outcome: Which food dye diffuses first.

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Which of the following statements are true about the international system of measurement?

anygoal [31]

The International System Units or the SI units is scientific method of expressing the magnitudes or quantities of important natural phenomena. There are seven base units in the system, from which other units are derived. This system was formerly called the meter-kilogram-second (MKS) system.

8 0

2 years ago

Susan plans to grow cabbages and broccoli in her vegetable garden. Cabbages and broccoli grow best in clay soil. Which of these

irakobra [83]

The correct option is B.
As we are told in the question, the cabbage and broccoli grow best in clay soil. From the options we are given, it can be seen that it is only option B that has the highest amount of clay soil. The soil that will be used should be one that has the highest content of clay.

7 0

3 years ago

I need help with homework! what should i choose as the greatest british invention?

STatiana [176]

THE MINI Alec Issigonis, 1959
The Telephone Alexander Graham Bell, 1876

http://www.radiotimes.com/news/2013-01-08/the-50-greatest-british-inventions

4 0

3 years ago

A 3600 kg rocket traveling at 2900 m/s is moving freely through space on a journey to the moon. The ground controllers find that

Nana76 [90]

Answer:

m=417.24 kg

Explanation:

Given Data

Initial mass of rocket M = 3600 Kg

Initial velocity of rocket vi = 2900 m/s

velocity of gas vg = 4300 m/s

Θ = 11° angle in degrees

To find

m = mass of gas

Solution

Let m = mass of gas

first to find Initial speed with angle given

Vi=vi×tanΘ...............tan angle

Vi= 2900m/s × tan (11°)

Vi=563.7 m/s

Now to find mass

m = (M ×vi ×tanΘ)/( vg + vi tanΘ)

put the values as we have already solve vi ×tanΘ

m = (3600 kg ×563.7m/s)/(4300 m/s + 563.7 m/s)

m=417.24 kg

7 0

3 years ago

An object moving in circular motion has a mass of 15 kg and a centripetal acceleration of 10 m/s2. What is the centripetal force

sweet-ann [11.9K]

Answer:

1) A

2) C

3) B

4) A

5) Incomplete information(picture missing)

6) Incomplete information(picture missing)

7) Incomplete information(picture missing)

8) A

9) C

10) C

Explanation:

1) m = 15kg, a = $10ms^{-2}$ , F = ma = 15*10 = 150N

2) m = 3kg, v = $4ms^{-1}$ , r = 4m, F = $\frac{mv^{2} }{r}$

$\frac{3*4^{2} }{4}$ = 12N

3) a = $10ms^{-2}$ , r = 10m, v=?

F = $\frac{mv^{2} }{r}$ and F = ma

equating the two equations and cancelling a, we have:

$\frac{v^{2} }{r}$ = a

making v the subject of formula, we have:

v = $\sqrt{ar}$

= $\sqrt{100}$

= 10 $ms^{-1}$

4) r = 10m, v = $5ms^{-1}$ , a = ?

F = $\frac{mv^{2} }{r}$

F = ma

equating the above equations and making a subject of formula, we get:

a = $\frac{v^{2} }{r}$

a = 25/10 = 2.5 $ms^{-2}$

5) I can't find the picture associated with this question

6) I can't find the picture associated with this question

7) I can't find the picture associated with this question

8) F = $\frac{mv^{2} }{r}$

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = $v^{2}$

Now, if v is tripled

F = $(3v)^{2}$

F = 9 $v^{2}$

We can see that the force will be 9X greater than it was.

9) F = $\frac{mv^{2} }{r}$

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = $v^{2}$

Now, if v is doubled

F = $(2v)^{2}$

F = 4 $v^{2}$

We can see that the force will be 4X greater than it was.

10) F = $\frac{mv^{2} }{r}$

assuming m and v is unity, that is the values are 1 respectively

F = 1/r

if r is doubled,

F = 1/2 * 1/r

We can see that the force is 1/2 as big as it was

7 0

2 years ago