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allsm [11]
3 years ago
6

¿que nombre recibe la tendencia que presentan los cuerpos de mantener su estado de reposo o movimiento rectilíneo uniforme, al n

o existir fuerzas que actúen sobre ellos?​
Physics
1 answer:
Leni [432]3 years ago
6 0

Answer:

Inercia

Explanation:

<u>Leyes de Newton </u>

Las tres leyes de Isaac Newton explican los hechos relativos a la dinámica del movimiento en la llamada física clásica. Luego Eisntein demostró que esas teorías solo eran válidas a velocidades mucho menores a la de la luz.

La primera ley de Newton explica el porqué los cuerpos cambian su estado de movimiento, es decir, si están en reposo, se comienzan a mover y si se están moviendo, cambian su velociad y/o dirección. Eso se debe a que una fuerza neta desequilibrante actuó sobre el cuerpo imprimiéndole aceleración.

Esa ley también se conoce como la Ley de la Inercia, y la tendencia de los cuerpos a mantener su estado de movimiento o reposo, es la Inercia. Debo corregir el planteamiento de la pregunta, ya que si pueden haber fuerzas aplicadas sobre el cuerpo, pero si están todas en equilibrio, el cuerpo no se acelera. NO debe haber fuerza neta

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D. Humidity refers to the amount of water vapor in the air

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A man drags a 71-kg crate across the floor at a constant velocity by pulling on a strap attached to the bottom of the crate. The
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Answer:

T = 540 N   (to two significant digits)

Explanation:

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L is common to all terms, so divides out.

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An astronaut circles the earth in a satellite at an altitude of 150 km. If the diameter of his pupils is 2.0 mm and the average
Fiesta28 [93]

Answer:

d = 49.5 m

hence we can say it is conceivable that he can distinguish sports stadiums on earth's surface but in Private houses? Cars? it can not becayuse they are are very small

Explanation:

Given data

altitude = 150 km

diameter = 2.0 mm

wavelength = 550 nm

to find out

is it conceivable that he can distinguish sports stadiums

solution

we will apply here formula that is

∅ = 1.2 λ  / D

put here λ  = 550 ×10^{-9} m and D = 2 ×10^{-3} m

∅ = (1.2 ) 550 ×10^{-9}  / 2 ×10^{-3}

∅ = 3.30 ×10^{-4}   rad

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d = 150  × 10^{3} × 3.30 ×10^{-4}  

d = 49.5 m

hence we can say it is conceivable that he can distinguish sports stadiums on earth's surface but in Private houses? Cars? it can not becayuse they are are very small

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