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prohojiy [21]
3 years ago
9

What best describes hooke’s equation?

Physics
1 answer:
NeX [460]3 years ago
6 0
The spring balance
F =ke
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There is a simple pattern for determining if a binary number is odd. what is it and why does this pattern occur
frez [133]
The answer to this question would be the least number (right most number).

If you add an even number with even number, the result should be even. But if there is just one odd number added, it will be odd.
In binary, all the number is multiplied by 2^{x}. It is pretty clear that all the number should be even beside the first/lowest multiplier 2^{0}  which has potential to be 1. 
5 0
4 years ago
Read 2 more answers
Drying of Cassava (Tapioca) Root. Tapioca flour is used in many countries for bread and similar products. The flour is made by d
svet-max [94.6K]
Yea it would be 500 minus 10 is 490
5 0
3 years ago
A rain drop of radius 0.3mm has terminal velocity 1m/s in air. The viscosity of air is 18X10-5 poise, then viscous force is​
dimaraw [331]

Answer:

F = 1.0178 × 10^(-2) dyne

Explanation:

From stokes law, the viscous force also known as drag force on rain drop is given by the formula;

F = 6πηrv

Where;

η is viscosity

r is radius

v is velocity

We are given;

η = 18 × 10^(-5) poise

r = 0.3 mm = 0.03 cm

v = 1 m/s = 100 cm/s

Thus;

F = 6π × 18 × 10^(-5) × 0.03 × 100

F = 1.0178 × 10^(-2) dyne

8 0
3 years ago
The coefficients of friction between the 20-kg crate and the inclined surface are µ,8 = 0.24 and J.lk = 0.22. If the crate start
Yanka [14]

Answer:5.60 m/s

Explanation:

Given

Coefficient of static friction \mu _s=0.24

Coefficient of kinetic friction \mu _k=0.22

mass of crate m=20\ kg

Force applied F=200\ N

maximum static Friction F_s=\mu _sN

N=mg

F_s=0.24\times 20\times 9.8

F_s=47.04\ N

thus applied force is greater than Static friction therefore kinetic friction will come into play

F_k=\mu _kN

F_k=0.22\times 20\times 9.8=43.12\ N

net Force on crate F-F_k=ma

a=\frac{200-43.12}{20}=7.84\ m/s^2

Magnitude of velocity can be obtained by using

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

here initial velocity is zero as crate start from rest

v^2-0=2\times 7.84\times 2

v=\sqrt{31.37}

v=5.60\ m/s                                          

7 0
4 years ago
Light of wavelength 645 nm is incident on a double slit. The angle between the central bright fringe and the second dark fringe
kumpel [21]

Answer:

Slit separation, d=1.13\times 10^{-5}\ m

Explanation:

It is given that,

Wavelength of light, \lambda=645\ nm=645\times 10^{-9}\ m

The angle between the central bright fringe and the second dark fringe, \theta=4.9^{\circ}

In case of double slits, the condition for dark fringe is given by :

d\ sin\theta=(n-\dfrac{1}{2})\lambda

n = 2

d\ sin\theta=\dfrac{3}{2}\lambda

d=\dfrac{3\lambda}{2\ sin\theta}

d=\dfrac{3\times 645\times 10^{-9}}{2\ sin(4.9)}

d=1.13\times 10^{-5}\ m

So, the slit separation is 1.13\times 10^{-5}\ m. Hence, this is the required solution.

8 0
3 years ago
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