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2 years ago

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How much heat is required to change the temperature of two cups of water (500 g) from room temperature (25◦C) to boiling? Specif

ic heat of water is c=4.184 J/(g oC) a 78.5 kJ b 15.7 kJ c 157 kJ d 1.57 kJ

1 answer:

NNADVOKAT [17]2 years ago

6 0

Answer:

c. 157 KJ

Explanation:

Q= mC dT dT= 100°C(boiling point) - 25°C=75°C

Q= (500 g * 4.184 J/g °C * 75 °C)

Q= 156900 J= 157 KJ

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true or false does the octet rule state that all atoms want to have 8 valence electrons in the outer shell

ladessa [460]

Answer:

false?

Explanation:

The octet rule refers to the tendency of atoms to prefer to have eight electrons in the valence shell. When atoms have fewer than eight electrons, they tend to react and form more stable compounds

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2 years ago

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iren [92.7K]

Answer:

B

Explanation:

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2 years ago

For each trial, compute the mol of titrant; (molarity x L) and keep the number of significant figures to 4.

MrMuchimi

Answer:

Trial Number of moles

1 0.001249mol

2 0.001232mol

3 0.001187 mol

Explanation:

To calculate the <em>number of moles of tritant</em> you need its<em> molarity</em>.

Since the<em> molarity</em> is not reported, I will use 0.1000M (four significant figures), which is used in other similar problems.

<em>Molarity</em> is the concentration of the solution in number of moles of solute per liter of solution.

In this case the solute is <em>NaOH</em>.

The formula is:

$Molarity=\dfrac{\text{Number of moles of solute}}{\text{Volume of solution in liters}}$

Solve for the <em>number of moles:</em>

$\text{Number of moles}=Molarity\times Volume\text{ }in\text{ }liters$

Then, using the molarity of 0.1000M and the volumes for each trial you can calculate the number of moles of tritant.

Trial mL liters Number of moles

1 12.49 0.01249 0.01249liters × 0.1000M = 0.001249mol

2 12.32 0.01232 0.01232liters × 0.1000M = 0.001232mol

3 11.87 0.01187 0.01187liters × 0.1000M = 0.001187 mol

3 0

2 years ago

Read 2 more answers

Which of the following is not an example of a chemical change?

Eva8 [605]

D I think.. hopefully it helps a little

8 0

2 years ago

Methane gas and oxygen gas react to form water vapor and carbon dioxide gas. What volume of water would be produced by this reac

yanalaym [24]

volume of H₂O = 7.2 L

Explanation:

The combustion reaction of methane (CH₄):

CH₄ + 2 O₂ → CO₂ + 2 H₂O

Now we calculate the number of moles of methane using the following formula:

number of moles = volume / 22.4 (L/mole)

number of moles of CH₄ = 3.6 / 22.4

number of moles of CH₄ = 0.16 moles

Taking in account the chemical reaction, we devise the following reasoning:

if 1 mole of CH₄ produce 2 moles of H₂O

then 0.16 moles of CH₄ produce X moles of H₂O

X = (0.16 × 2) / 1 = 0.32 moles of H₂O

And now we can calculate the volume of water (H₂O) produced by the reaction:

number of moles = volume / 22.4 (L/mole)

volume = number of moles × 22.4 (L/mole)

volume of H₂O = 0.32 × 22.4

volume of H₂O = 7.2 L

Learn more about:

combustion reaction

brainly.com/question/14122510

#learnwithBrainly

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2 years ago