Question

Be sure to answer all parts. Butane gas is compressed and used as a liquid fuel in disposable cigarette lighters and lightweight camping stoves. Suppose a lighter contains 7.96 mL of butane (d = 0.579 g/mL). (a) How many grams of oxygen are needed to burn the butane completely?

Answer 1

Answer:

The correct answer will be "4.60 g".

Explanation:

The given values are:

Volume of Butane = 7.96 mL

Density = 0.579 g/mL

As we know,

⇒  $Mass \ of \ Butane = Density\times Volume$

On putting the estimated values, we get

⇒                              $=0.579\times 7.96$

⇒                              $=4.60 \ g$