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3 years ago

How do I solve this?? ok having a hard time BRAINLIST

Chemistry

1 answer:

USPshnik [31]3 years ago

8 0

Answer:

1) 6(1/2)

2) 8(4/5)

Explanation:

1) 7 - 1/2 = 7/1 - 1/2 = 14/2 - 1/2 = 13/2 = 6(1/2)

2) 11(2/5) - 2(3/5) = 57/5 - 13/5 = 44/5 = 8(4/5)

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Nitrogen dioxide (NO2) cannot be obtained in a pure form in the gas phase because it exists as a mixture of NO2 and N2O4. At 16°

Pavel [41]

Answer:

PNO₂ = 0.49 atm

PN₂O₄ = 0.45 atm

Explanation:

Let's begin with the equation of ideal gas, and derivate from it an equation that involves the density (ρ = m/V).

PV = nRT

n = m/M (m is the mass, and M the molar mass)

$PV = \frac{m}{M}RT$

$PxM = \frac{m}{V}RT$

PxM = ρRT

ρ = PxM/RT

With the density of the gas mixture, we can calculate the average of molar mass (Mavg), with the constant of the gases R = 0.082 atm.L/mol.K, and T = 16 + 273 = 289 K

$2.7 = \frac{0.94xMavg}{0.082x289}$

0.94Mavg = 63.9846

Mavg = 68.0687 g/mol

The molar mass of N is 14 g/mol and of O is 16 g/mol, than $M_{NO2} = 46$ g/mol and $M_{N2O4} = 96$ g/mol. Calling y the molar fraction:

$Mavg = M_{NO2}y_{NO2} + M_{N2O4}y_{N2O4}$

And,

$y_{NO2} + y_{N2O4} = 1$

$y_{N2O4} = 1 - y_{NO2}$

So,

$68.0687 = 46y_{NO2} + 92x(1 - y_{NO2})$

$68.0687 - 92 = 46y_{NO2} - 92y_{NO2}$

$46y_{NO2} = 23.9313$

$y_{NO2} = 0.52$

$y_{N2O4} = 0.48$

The partial pressure is the molar fraction multiplied by the total pressure so:

PNO₂ = 0.52x0.94 = 0.49 atm

PN₂O₄ = 0.48x0.94 = 0.45 atm

8 0

3 years ago

On a hot summer day you and some friends decide you want to cool down your pool. Determine the mass of ice you would need to add

sergeinik [125]

Answer: The mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is $16.14 \times 10^{4}$ kg.

Explanation:

We know that relation between heat energy and specific heat is as follows.

q = $m \times S \times \Delta T$

As density of water is 1 kg/L and volume is given as 400,000 L. Therefore, mass of water is as follows.

Mass of water = Volume × Density

= $400,000 L \times 1 kg/L$

= 400,000 kg

or, = $400,000 \times 10^{3}$ g (as 1 kg = 1000 g)

Specific heat of water is 4.2 J/gm K. Therefore, change in temperature is as follows.

$\Delta T$ = 305 K - 273 K

= 32 K

Now, putting the given values into the above formula and calculate the heat energy as follows.

q = $m \times S \times \Delta T$

= $400,000 \times 10^{3} \times 4.2 \times 32 K$

= $5376 \times 10^{7}$ J

or, = $5376 \times 10^{4}$ kJ

According to the enthalpy of melting of ice 333 kJ/Kg of energy absorbed by by 1 kg of ice. Hence, mass required to absorb energy of $5376 \times 10^{4}$ kJ is calculated as follows.

Mass = $\frac{5376 \times 10^{4} kJ}{333 kJ/Kg} \times 1 kg$

= $16.14 \times 10^{4}$ kg

Thus, we can conclude that the mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is $16.14 \times 10^{4}$ kg.

3 0

3 years ago

How many moles of gas occupy 56.3 L at 0.899 atm and 20.0°C?

zzz [600]

Answer:

n = 2.1 mol

Explanation:

Given data:

Number of moles of gas = ?

Volume of gas = 56.3 L

Pressure of gas = 0.899 atm

Temperature of gas = 20°C (20+273 = 293 k)

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

0.899 atm × 56.3 L = n × 0.0821 atm.L/ mol.K × 293 k

50.614 atm.L = n × 24.055 atm.L/ mol

n = 50.614 atm.L / 24.055 atm.L/ mol

n = 2.1 mol

3 0

3 years ago

What elements make up this compound? Check all that apply.

vladimir2022 [97]

What compound are you trying to show

5 0

3 years ago

Read 2 more answers

Which formula has a mass of 207g

skad [1K]

Empirical formula has a mass of 207g

5 0

3 years ago

How do I solve this?? ok having a hard time BRAINLIST​

How do I solve this?? ok having a hard time BRAINLIST