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LUCKY_DIMON [66]
3 years ago
13

A student needs to convert a volume of 3 Tbsp (tablespoons) to mL. The student finds out that 1 tablespoon is equivalent to 14.7

9 mL. Choose the correct numbers and units that must be found in the conversion factor to solve this problem.
Chemistry
1 answer:
garri49 [273]3 years ago
3 0

Answer:

The conversion factor is 14.79 mL/Tbsp.

Explanation:

To do an unity conversiton, we can make a factor by a ratio transformation:

3 Tbsp * \frac{14.79 mL}{1Tbsp}

So, the conversion factor is 14.79 mL/Tbsp and 3 Tbsp has 44.37 mL.

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What do atoms consist of?
kolbaska11 [484]
Charge and uncharged particles
7 0
3 years ago
Read 2 more answers
Na +H₂O- NaOH +H₂ balance
Whitepunk [10]

Hey there!

Na + H₂O → NaOH + H₂

First, balance O.

One on the left, one on the right. Already balanced.

Next, balance H.

Two on the left, three on the right. Let's add a coefficient of 2 in front of NaOH and a coefficient of 2 in front of H₂O, so we have 4 on each side.

Na + 2H₂O → 2NaOH + H₂

Lastly, balance Na.

One on the left, two on the right. Add a coefficient of 2 in front of Na.

2Na + 2H₂O → 2NaOH + H₂  

This is our final balanced equation.

Hope this helps!

7 0
3 years ago
A sample of N2O3(g) has a pressure of 0.046 atm . The temperature (in K) is then doubled and the N2O3 undergoes complete decompo
iogann1982 [59]

Answer:

0.184 atm

Explanation:

The ideal gas equation is:

PV = nRT

Where<em> P</em> is the pressure, <em>V</em> is the volume, <em>n</em> is the number of moles, <em>R</em> the constant of the gases, and <em>T</em> the temperature.

So, the sample of N₂O₃ will only have its temperature doubled, with the same volume and the same number of moles. Temperature and pressure are directly related, so if one increases the other also increases, then the pressure must double to 0.092 atm.

The decomposition occurs:

N₂O₃(g) ⇄ NO₂(g) + NO(g)

So, 1 mol of N₂O₃ will produce 2 moles of the products (1 of each), the <em>n </em>will double. The volume and the temperature are now constants, and the pressure is directly proportional to the number of moles, so the pressure will double to 0.184 atm.

5 0
3 years ago
Silicon carbide (SiC) is an important ceramic material made by reacting sand (silicon dioxide, SiO2) with powdered carbon at a h
makkiz [27]

Answer:

Percent yield of SiC is 77.0%.

Explanation:

Balanced reaction: SiO_{2}+3C\rightarrow SiC+2CO

Molar mass of SiC = 40.11 g/mol

Molar mass of SiO_{2} = 60.08 g/mol

So, 100.0 kg of SiO_{2} = \frac{100.0\times 10^{3}}{60.08} moles of SiO_{2} = 1664 moles of SiO_{2}

According to balanced equation, 1 mol of SiO_{2} produces 1 mol of SiC

Therefore, 1664 moles of SiO_{2} produce 1664 moles of SiC

Mass of 1664 moles of SiC = (1664\times 40.11)g = 66743g = 66.74 kg (4 sig. fig.)

Percent yield of SiC = [(actual yield of SiC)/(theoretical yield of SiC)]\times 100%

                                 = \frac{51.4kg}{66.74kg}\times 100 %

                                 = 77.0%

4 0
3 years ago
What is the pressure of 1.27 L of a gas at 288°C, if the gas had a volume of 875 ml at
lyudmila [28]

The pressure of 1.27 L of a gas at 288°C, if the gas had a volume of 875 ml at 145 kPa and 176°C is 1.195 atm.

<h3>What is ideal gas equation?</h3>

Ideal gas equation of any gas will be represented as:
PV = nRT, where

P = pressure

V = volume

n = moles

R = universal gas constant

T = temperature

First we calculate the moles of gas, when the volume of gas 875 ml at

145 kPa and 176°C as:

n = (1.431atm)(0.875L) / (0.082L.atm/K.mol)(449.15K)

n = 1.252 / 36.83 = 0.033 moles

Now we measure the pressure of 0.033 moles of gas of 1.27 L of a gas at 288°C as:

P = (0.033mol)(0.082L.atm/K.mol)(561K) / (1.27L) = 1.195 atm

Hence required pressure of gas is 1.195 atm.

To know more about ideal gas equation, visit the below link:
brainly.com/question/555495

#SPJ1

3 0
2 years ago
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