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LUCKY_DIMON [66]

3 years ago

13

A student needs to convert a volume of 3 Tbsp (tablespoons) to mL. The student finds out that 1 tablespoon is equivalent to 14.7

9 mL. Choose the correct numbers and units that must be found in the conversion factor to solve this problem.

1 answer:

garri49 [273]3 years ago

3 0

Answer:

The conversion factor is 14.79 mL/Tbsp.

Explanation:

To do an unity conversiton, we can make a factor by a ratio transformation:

$3 Tbsp * \frac{14.79 mL}{1Tbsp}$

So, the conversion factor is 14.79 mL/Tbsp and 3 Tbsp has 44.37 mL.

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Really need help on this thing plz someone... help number 2 and 3:(

olasank [31]

Answer:

I don't have one sorry

Explanation:

it's because I can't see the question I don't know it I'm sorry dude

8 0

2 years ago

Please help thaank youu

krek1111 [17]

First, let's start off by finding the mass of this whole hydrate.
(Note: the unit of measurement for mass will be amu)

Let's find the molecular mass of each element.
$Co=58.933$
$Cl=35.45$
$H=1.008$
$O=15.999$

Now, let's find the mass of each compound.

$CoCl_2=58.933+2(35.45)=129.833$
$H_2O=2(1.008)+15.999=18.015$

We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.

$6(18.015)=108.09$
$129.833+108.09=237.923$

Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).

$\dfrac{108.09}{237.923}$

$\approx0.45431$

Turn that into a percentage and you get 45.431%.
Hope this helps! :)

6 0

3 years ago

1.00 L of gas at a standard temperature and pressure is compressed to 473mL. What is the new pressure of the gas?

Nadusha1986 [10]

Answer:

The pressure of the gas is 2.11 atm.

Explanation:

From the given,

$V_{1}=1.00\,L$

$P_{1}=1\,atm$

$P_{2}=?$

$V_{2}=473\,ml=0.473\,L$

$P_{1}V_{1}=P_{2}V_{2}$

$(1)(1)=(0.473)(P_{2})$

$P_{2}=\frac{(1)(1)}{0.473}=2.11$

Therefore, The pressure of the gas is 2.11 atm.

6 0

3 years ago

Plz answer this i will mark brainly like and ratr

matrenka [14]

Answer:

answer what ?

Explanation:

4 0

3 years ago

44.8% of a 250. mL acid solution is used in an experiment, what volume of acid (in mL) was used?

postnew [5]

Answer:

112 mL

Explanation:

The formula for percent by volume is

$\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%$

If you have 250 mL of a solution that is 44.8 % v/v,

$\begin{array}{rcl}44.8\, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\44.8 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{44.8 \times 250\text{ mL}}{100}\\\\ & = & \textbf{112 mL}\\\end{array}$

7 0

3 years ago