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Effectus [21]
3 years ago
11

How many moles of gas occupy 56.3 L at 0.899 atm and 20.0°C? ​

Chemistry
1 answer:
zzz [600]3 years ago
3 0

Answer:

n = 2.1 mol

Explanation:

Given data:

Number of moles of gas = ?

Volume of gas = 56.3 L

Pressure of gas = 0.899 atm

Temperature of gas = 20°C (20+273 = 293 k)

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

0.899 atm × 56.3 L  = n × 0.0821 atm.L/ mol.K  × 293 k

50.614 atm.L = n × 24.055 atm.L/ mol

n = 50.614 atm.L / 24.055 atm.L/ mol

n = 2.1 mol

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Answer:

Quantum numbers of the outermost electron in potassium:

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Explanation:

Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the 4s orbital (fourth s orbital.)

The quantum number n (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence, n = 4 for this electron.

The quantum number l (the angular momentum quantum number) specifies the shape (s, p, d, etc.) of an electron. l = 1 for s\! orbitals (such as the one that contains this electron.

Quantum numbers n and l specify the shape of an orbital. On the other hand, the magnetic quantum number m_l specifies the orientation of these orbitals in space.

However, s orbitals are spherical. Regardless of the value of n, the only possible m_l value for electrons in s\! orbitals is m_l = 0.

The spin quantum number m_s distinguishes between the two electrons in an orbital. The two possible values of m_s \! are (+1/2) and (-1/2). Typically, the first electron in an orbital is assigned an upward (\uparrow) spin, which corresponds to m_s = (+1/2).

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Answer:

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Let g denote the strength of the gravitational field at a certain point. If the mass of an object is m, its weight at that point will be m \cdot g.

Indeed, g \approx 9.81\; \rm N \cdot kg^{-1} on many places of the earth. However, this value is accurate only near the sea level. The equation for universal gravitation is a more general way for finding the strength of the gravitational field at an arbitrary height. Let G denote the constant of universal gravitation, and let M denote the mass of the earth. At a distance r from the center of the earth (where

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The elevation of many places in Bhutan are significantly higher than that of many places in India. Therefore, a sack of potato in Bhutan will likely be further away from the center of the earth (larger r) compared to a sack of potato in India.

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On the other hand, the weight of an object of fixed mass is proportional to the gravitational field strength. Therefore, the same bag of potatoes will have a smaller weight at most places in Bhutan compared to most places in India.

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