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igor_vitrenko [27]
3 years ago
8

An electron (m=9.11x10^-31 kg) moves in a circle whose radius is 2.00x10^-2 m. If the force acting on the electron is 4.60x10^-1

4 N, what is it's speed?
Physics
1 answer:
Crank3 years ago
4 0

Answer:

The speed of the electron is 3.178\times 10^7\ m/s.

Explanation:

Given:

Mass of electron is, m=9.11\times 10^{-31}\ kg

Radius of circle is, R=2.00\times 10^{-2}\ m

Force acting on the electron is, F=4.60\times 10^{-14}\ N

Now, we know that, for a circular turn, the force acting on the electron is due to centripetal force. Centripetal force acting on the electron is given as:

F=\frac{mv^2}{R}

Here, 'v' is the velocity of the electron.

Now, plug in all the given values and solve for 'v'. This gives,

4.60\times 10^{-14}=\frac{9.11\times 10^{-31}v^2}{2.00\times 10^{-2}}\\\\9.11\times 10^{-31}v^2=4.60\times 10^{-14}\times 2.00\times 10^{-2}\\\\9.11\times 10^{-31}v^2=9.2\times 10^{-16}\\\\v^2=\frac{9.2\times 10^{-16}}{9.11\times 10^{-31}}\\\\v^2=1.01\times 10^{15}\\\\v=\sqrt{1.01\times 10^{15}}\\\\v=3.178\times 10^7\ m/s

Therefore, the speed of the electron is 3.178\times 10^7\ m/s.

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A 15-µF capacitor is charged to 40 V and then connected across an initially uncharged 25-µF capacitor. What is the final potenti
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Answer:

24volts

Explanation:

If a 15-µF capacitor is charged to 40V, the charge across the capacitor can be calculated using the formula;

Q = CV where;

Q is the charge flowing across the capacitor

C is the capacitance of the capacitor. = 15-µF

V is the voltage = 40V

Q = 15×10^-6×40

Q = 0.0006coulombs

If the charge of 0.0006coulombs is then connected across an initially uncharged 25-µF capacitor, the potential difference across the 25-µF can be calculated using the initial expression;

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V = Q/C

V = 0.0006/25×10^-6

V = 24Volts

Therefore, the final potential difference across the 25-µF capacitor will be 24volts

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3 years ago
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when electrical energy is used what type of energy is also produced and considered to be waste energy?​
Dima020 [189]

Answer:

<em>Thermal energy</em>

Explanation:

<u>Electrical Energy </u>

The electrical energy has been found to be an excellent resource to power our modern lifestyle. It can be produced in several ways including hydroelectrical plants, thermal plants, nuclear plants, solar panels, among many others. Each one of them converts different types of energy into electrical energy.

When converting to electrical energy, some equipment is needed, like generators, transformers, cables, circuit breakers, and every kind of devices with specific functions to have a good and safe electrical service. Each device has an internal resistance that opposes the flow of current. The resistances produce thermal energy as a result of current flowing through them. It's not possible to avoid this waste of energy, electrical engineers do their best to use better materials and configurations to reduce the thermal waste to a minimum.

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A solid conducting sphere with radius R that carries positive charge Q is concentric with a very thin insulating shell of radius
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Explanation:

Gauss Law relates the distribution of electric charge to the resulting electric field.

Applying Gauss's Law,

                              EA = Q / ε₀

Where:

E is the magnitude of the electric field,

A is the cross-sectional area of the conducting sphere,

Q is the positive charge

ε₀ is the permittivity

We be considering cases for the specified regions.

<u>Case 1</u>: When r < R

The electric field is zero, since the enclosed charge is equal to zero

                                            E(r) = 0

<u>Case 2</u>: When R < r < 2R

The enclosed charge equals to Q, then the electric field equals;

                              E(4πr²) = Q / ε₀

                              E = Q / 4πε₀r²

                              E = KQ /r²

Constant K = 1 / 4πε₀ = 9.0 × 10⁹ Nm²/C²

<u>Case 3</u>: When r > 2R    

The enclosed charge equals to Q, then the electric field equals;

                               E(4πr²) = 2Q / ε₀

                               E = 2Q / 4πε₀r²

                               E = 2KQ /r²        

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